we have
6x+3y=12 -----> line p
Find the slope
3y=-6x+12
y=-2x+4
m=-2
-4x=2y-2 -----> line Q
2y=-4x+2
y=-2x+1
m=-2
therefore
the lines are parallel because their slopes are equal
Answer:
The correct option is A
Step-by-step explanation:
The given expression is:
√10/4√8
We have to eliminate the √ from the denominator
4√8 = (2^3)^1/4
Multiply the whole expression by (2)^1/4
=(2)^1/4 * √10/ 2^(1/4)*(2^3)^(1/4)
= 2^(1/4) · 10^(2/4) / 2^1/4+3/4
=2^(1/4) · 10^(2/4) / 2^1+3/4
=2^(1/4) · 10^(2/4) / 2^4/4
=2^(1/4) · 10^(2/4) /2
=2^(1/4) · 100^(1/4) /2
=200^1/4 /2
= 4√200 /2
Thus the correct option is A....
7 is the prime factor of 210
<span>Solving for the slope using points ( (−4, 15), (0, 5)</span>
M = ( 15 – 5) / ( -4 – 0) = -5 / 2
Solving for b
<span>
Y = mx + b</span>
5 = 0(-5/2) + b
B = 5
So the linear function is
<span>Y = (-5/2) x + 5</span>
Answer:
d)X=4 or x=-2
Step-by-step explanation:
X²-2x=8
X²-2x-8=0
(x-4)(x+2)=0
X-4=0 or x+2=0
X=4 or x=-2
