Assume this is f(x)=57.8(1.02)ˣ. This is a 2% increase each year.
When f(x)=200, 57.8(1.02)ˣ=200, (1.02)ˣ=200/57.8
Taking logs, xlog(1.02)=log(200/57.8), x= log(200/57.8)/log(1.02)=62.685.
Add 1960 to 62.685=2023 approx.
First, find the number of quarters that are dated 2005 by multiplying 38*(3/5)
You get 22.8, so you round that to the nearest whole number (23)
Then, since each quarter is worth ($.25) you multiply the number of coins by the worth.
23*.25=$5.75
m∠5 = 142°
Solution:
Line l and m are parallel.
<em>Sum of the adjacent angles in a straight line is 180°.</em>
⇒ 38° + m∠7 = 180°
⇒ m∠7 = 180° – 38°
⇒ m∠7 = 142°
∠5 and ∠7 are corresponding angles.
<em>If two parallel lines are cut by a transversal, then the corresponding angles on the same side are congruent.</em>
⇒ ∠5 ≅ ∠7
⇒ m∠5 = m∠7
⇒ m∠5 = 142°
Therefore m∠5 = 142°.
Charging: +2/min <span>percentage points.
Using: -5/min percentage points.
</span>Amount of time Famke used her phone: x
Amount of time Famke charge her phone: 2x
Famke gained 2x*(2/min)=x*(4/min) percentage points.
Over this period <span>her phone lost 10 percentage points→
x*(5/min)-x*(4/min)=10⇒x*(1/min)=10
x=10</span>
This means that she used her phone for 10 minutes and charged it for 20 minutes.
