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qwelly [4]
2 years ago
9

Solve 63 – x = 62 for x. A. x = 1 B. x = 9 C. x = –1 D. x = –6

Mathematics
1 answer:
salantis [7]2 years ago
7 0
X equals POSITIVE one. so 63 minus one equals 62. the answer is a
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Find the area of the region under the graph of the function f on the interval [1, 8].
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Tell whether the lines through the given points are parallel, perpendicular, or neither. (-3,1), (1,9), (-2-9), (-1,-7)​
Brrunno [24]

Answer:

parallel

Step-by-step explanation:

all the details are in the attached picture.

4 0
3 years ago
The longest spin of a basketball on one finger is 255 minutes.about how many hours is that
lidiya [134]

The longest spin of a basketball on one finger is 255 minutes or 4.25 hours.

Step-by-step explanation:

the longest spin of a basketball on one finger is 255 minutes.

We need to find how many hours is that.

So, we need to convert 255 minutes into hours.

We know that,

60 minutes = 1 hour

Using Unitary method:

60 minutes = 1 hour

1 minute = 1/60 hour

255 minutes = 1/60 * 255 hour

255 minutes = 255/60 hour = 4.25 hour

255 minutes is 4.25 hour.

So, The longest spin of a basketball on one finger is 255 minutes or 4.25 hours.

Keywords: Convert Minutes to Hour

Learn more about Convert Minutes to Hour at:

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4 0
2 years ago
A particular fruit's weights are normally distributed, with a mean of 733 grams and a standard deviation of 9 grams. The heavies
RoseWind [281]

Answer:

The heaviest 5% of fruits weigh more than 747.81 grams.

Step-by-step explanation:

We are given that a particular fruit's weights are normally distributed, with a mean of 733 grams and a standard deviation of 9 grams.

Let X = <u><em>weights of the fruits</em></u>

The z-score probability distribution for the normal distribution is given by;

                              Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean weight = 733 grams

            \sigma = standard deviation = 9 grams

Now, we have to find that heaviest 5% of fruits weigh more than how many grams, that means;

                    P(X > x) = 0.05       {where x is the required weight}

                    P( \frac{X-\mu}{\sigma} > \frac{x-733}{9} ) = 0.05

                    P(Z > \frac{x-733}{9} ) = 0.05

In the z table the critical value of z that represents the top 5% of the area is given as 1.645, that means;

                               \frac{x-733}{9}=1.645

                              {x-733}}=1.645\times 9

                              x = 733 + 14.81

                              x = 747.81 grams

Hence, the heaviest 5% of fruits weigh more than 747.81 grams.

8 0
2 years ago
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