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2 years ago

Solve 63 – x = 62 for x. A. x = 1 B. x = 9 C. x = –1 D. x = –6

Mathematics

1 answer:

salantis [7]2 years ago

7 0

X equals POSITIVE one. so 63 minus one equals 62. the answer is a

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The curved part of this figure is a semicircle. What is the best approximation for the area of this figure? 18+12.125π units² 36

andreyandreev [35.5K]

Answer:

18+12.125π units²

Step-by-step explanation:

The diameter of the semicircle can be found by the use Pythagoras theorem.

Δx²+Δy²=d²

Δx=3--1=4

Δy=3--6=9

d²=4²+9²

d=√(16+81)

Area=πr²/2

=π×(√(16+81)/2)²÷2

=[π×(97)/4]/2

=97π/8

=18+12.125π units²

97π/8 is equivalent to 18+12.125π units²

3 0

2 years ago

A bus stops at the station near Kylie's house every 1 hours . Which expression could be used to find the number of times the bus

anastassius [24]

Answer:

Step-by-step explanation:

24 x 1 1/4

5 0

2 years ago

This year, a small business had a total revenue of $40,700. If this is 26% less than their total revenue the previous year, what

Virty [35]

26% less than a value is best found by multiplying by (100 - 26)% = 74% = 0.74
So previous year x 0.74 = 40,700
Previous year = 40,700 / 0.74 = $55,000

8 0

2 years ago

X and y<br> are supplementary angles. y<br> measures 156<br> What is the measure of a?

Troyanec [42]

Supplementary angles need to add up to 180 degrees.

Subtract Y from 180:

X = 180 - 156 = 24

X = 24 degrees

6 0

2 years ago

At 10 A.M. a plane leaves Boston, Massachusetts, for Seattle, Washington, a distance of 3000 mi. One hour later a plane leaves S

Reil [10]

Answer:

The plane from Seattle will pass the plane from Boston after 4.5 hours of its departure from the Seattle.

Step-by-step explanation:

Plane-1 = Boston, Massachusetts - Seattle, Washington at 10:00 AM

Plane-2= Seattle, Washington - Boston, Massachusetts at 11:00 AM

Speed of plane-1 = 300 mile/hour

Distance covered by plane-1 in 1 hour = 300 mile/h × 1 h = 300 mile

Distance between plane-1 and plane 2 after 1 hour :

= 3000 mile - 300 mile = 2700 mile

Let the distance covered by plane-1 after 1 hour be x in t time where it will pass plane-2.

Let the distance covered by plane-2 be y in t time where it will pass plane-1.

x + y = 2700 ...[1]

Speed of plane-1 = 300 mile/hour

$300 mile/h=\frac{x}{t}$ ..[2]

Speed of plane-2 = 300 mile/hour

$300 mile/h=\frac{y}{t}$ ..[3]

Putting value of t from [2] in [3];

$t=\frac{x}{300 mile/h}$

$300 mile/h=\frac{y}{\frac{x}{300 mile/h}}$

$\frac{x}{300 mile/h}=\frac{y}{300 mile/h}$

x = y

In [1] put x = y

y + y = 2700 miles

2y = 2700 miles

y = 1,350 mile

For the value of t, put the value of y in [3]:

$t=\frac{1,350 mile}{300 mile/h}=4.5 hour$

The plane from Seattle will pass the plane from Boston after 4.5 hours of its departure from the Seattle.

5 0

2 years ago