1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Julli [10]
2 years ago
13

Difference between a bowling ball and a baseball

Mathematics
2 answers:
denis23 [38]2 years ago
6 0
A bowling ball weighs a lot more than a baseball.
AlladinOne [14]2 years ago
4 0
A bowling ball is way heavier than a baseball and the heavier it is the harder and fater the speed
You might be interested in
Which expression is equivalent to 54n-20m+6n
Eva8 [605]

Answer:

C. 594 > -11n

Step-by-step explanation:

i took the test on edgen

4 0
3 years ago
Read 2 more answers
Write an ordered pair corresponding to the point G.
Tasya [4]

Answer:

The ordered pair is (-4,2) this is the ordered pair because x=-4 and the y=2

Step-by-step explanation:


4 0
3 years ago
Read 2 more answers
the loudness, L, measured i in decibels (Db), of a sound intencity, I, measured in watts per square meter, is defined as L=10log
Jet001 [13]

Answer: D, 110 !!!

Step-by-step explanation:

8 0
3 years ago
What is an equation of the line in slope intercept form? M=2/3 and y intercept is (0,-3)
lana66690 [7]

Answer:

y= (2/3)x -3

Step-by-step explanation:

M is equal to the slope in y=mx+b form. And the y intercept is equal to (0, -3), therefore the b part of the formula is -3.

6 0
3 years ago
Find the area of the following<br> kite:<br> A = [?] m²<br> 40 m<br> 16 m<br> 16 m<br> 6 m
Rama09 [41]

Answer:

Area_{kite}=736m^2

Step-by-step explanation:

There are a few methods to find the area of this figure:

1. kite area formula

2. 2 triangles (one top, one bottom)

3. 2 triangles (one left, one right)

4. 4 separate right triangles.

<h3><u>Option 1:  The kite area formula</u></h3>

Recall the formula for area of a kite:  Area_{kite}=\frac{1}{2} d_{1}d_{2} where d1 and d2 are the lengths of the diagonals of the kite ("diagonals" are segments that connect non-adjacent vertices -- in a quadrilateral, vertices that are across from each other).

If you've forgotten why that is the formula for the area of a kite, observe the attached diagram: note that the kite (shaded in) is half of the area of the rectangle that surrounds the kite (visualize the 4 smaller rectangles, and observe that the shaded portion is half of each, and thus the area of the kite is half the area of the large rectangle).

The area of a rectangle is Area_{rectangle}=bh, sometimes written as Area_{rectangle}=bh, where w is the width, and h is the height of the rectangle.

In the diagram, notice that the width and height are each just the diagonals of the kite.  So, the <u>Area of the kite</u> is <u>half of the area of that surrounding rectangle</u> ... the rectangle with sides the lengths of the kite's diagonals.Hence, Area_{kite}=\frac{1}{2} d_{1}d_{2}

For our situation, each of the diagonals is already broken up into two parts from the intersection of the diagonals.  To find the full length of the diagonal, add each part together:

For the horizontal diagonal (which I'll call d1): d_{1}=40m+6m=46m

For the vertical diagonal (which I'll call d2): d_{2}=16m+16m=32m

Substituting back into the formula for the area of a kite:

Area_{kite}=\frac{1}{2} d_{1}d_{2}\\Area_{kite}=\frac{1}{2} (46m)(32m)\\Area_{kite}=736m^2

<h3><u /></h3><h3><u>Option 2:  The sum of the parts (version 1)</u></h3>

If one doesn't remember the formula for the area of a kite, and can't remember how to build it, the given shape could be visualized as 2 separate triangles, the given shape could be visualized as 2 separate triangles (one on top; one on bottom).

Visualizing it in this way produces two congruent triangles.  Since the upper and lower triangles are congruent, they have the same area, and thus the area of the kite is double the area of the upper triangle.

Recall the formula for area of a triangle:  Area_{triangle}=\frac{1}{2} bh where b is the base of a triangle, and h is the height of the triangle <em>(length of a perpendicular line segment between a point on the line containing the base, and the non-colinear vertex)</em>.  Since all kites have diagonals that are perpendicular to each other (as already indicated in the diagram), the height is already given (16m).

The base of the upper triangle, is the sum of the two segments that compose it:  b=40m+6m=46m

<u>Finding the Area of the upper triangle</u>Area_{\text{upper }triangle}=\frac{1}{2} (46m)(16m) = 368m^2

<u>Finding the Area of the kite</u>

Area_{kite}=2*(368m^2)

Area_{kite}=736m^2

<h3><u>Option 3:  The sum of the parts (version 2)</u></h3>

The given shape could be visualized as 2 separate triangles (one on the left; one on the right).  Each triangle has its own area, and the sum of both triangle areas is the area of the kite.

<em>Note:  In this visualization, the two triangles are not congruent, so it is not possible to  double one of their areas to find the area of the kite.</em>

The base of the left triangle is the vertical line segment the is the vertical diagonal of the kite.  We'll need to add together the two segments that compose it:  b=16m+16m=32m.  This is also the base of the triangle on the right.

<u>Finding the Area of left and right triangles</u>

Area_{\text{left }triangle}=\frac{1}{2} (32m)(40m) = 640m^2

The base of the right triangle is the same length as the left triangle: Area_{\text{right }triangle}=\frac{1}{2} (32m)(6m) = 96m^2

<u>Finding the Area of the kite</u>

Area_{kite}=(640m^2)+(96m^2)

Area_{kite}=736m^2

<h3><u>Option 4:  The sum of the parts (version 3)</u></h3>

If you don't happen to see those composite triangles from option 2 or 3 when you're working this out on a particular problem, the given shape could be visualized as 4 separate right triangles, and we're still given enough information in this problem to solve it this way.

<u>Calculating the area of the 4 right triangles</u>

Area_{\text{upper left }triangle}=\frac{1}{2} (40m)(16m) = 320m^2

Area_{\text{upper right }triangle}=\frac{1}{2} (6m)(16m) = 48m^2

Area_{\text{lower left }triangle}=\frac{1}{2} (40m)(16m) = 320m^2

Area_{\text{lower right }triangle}=\frac{1}{2} (6m)(16m) = 48m^2

<u>Calculating the area of the kite</u>

Area_{kite}=(320m^2)+(48m^2)+(320m^2)+(48m^2)

Area_{kite}=736m^2

8 0
2 years ago
Other questions:
  • ???????? Help me plz
    13·2 answers
  • What number is 35% of 600?
    12·1 answer
  • Write a linear Write a linear function f with f(−9)=10 and f(−1)=−2.function f with f(−9)=10 and f(−1)=−2.
    9·1 answer
  • Which property is x ( y + z) = xy + xz
    5·1 answer
  • A car factory produces 100 cars in a day if C is the total number of cars produced in the days which equation represents the num
    14·1 answer
  • Tickets for an amusement park cost $10 for adults and 6 for children find the total cost of 2 adults and 3 children
    7·2 answers
  • Taylor and Jillian purchased pieces of gold jewelry. Taylor purchased 0.4 oz of 18-karat gold, and Jillian purchased 1.05 oz of
    13·1 answer
  • A sector has an area of 1/2 π and the central angles of 1/9 π radians. What is the area of the circle?
    12·1 answer
  • Which expression is equivalent to 3 to the fourth power times 3 to the 9th power
    12·1 answer
  • What is the distance between (-5.2, -6.1) and (7.9, -6.1) once you answer this, hows your day been? Have you drank water? If not
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!