1)Rewrite the table:
70, 49, 34.3, 24.01, 11.807 {The original size of the wound =70}
2) write the quotient of each number by the number before & notice the value:
49/70= 0.7
34.3/49 = 0.7
24.01/34.3 =0.7
16.0807/24.01 = 0.67 ≈0.7
You notice this is a geometric progression with r 0.7
The last term in a GP =ar^⁽ⁿ⁻¹⁾
3) Domain and Range of this function:
Last term = a₁.rⁿ⁻¹. let last term be y==> f(n) = y =70(0.7)ⁿ⁻¹
or f(n) = y = 70(0.7)ⁿ / 0.7==> f(n) = [(0.7)ⁿ ]/ 100.
This is a decreasing exponential function where the coefficient
raised to n is < 1.
The domain is for all n>= 0.
When n→∞, f(n)→0; For n=0==>f(n) =70. So the range of f(n) is:<=70
n = 2
distribute and simplify left side of equation
50 - 10n - 1 = 29
49 - 10n = 29 ( subtract 49 from both sides )
- 10n = 29 - 49 = - 20
n =
= 2
Answer:
IT'S THE ELLEN'S FACE FOR ME SBSJSHSSSWHSHSJSV
If it is asking if that equation is the quadratic formula, then the answer is false. The reason why is that the first 'b' should be negative
The quadratic formula is
