<span>48.76 + 22.98 + 7.53 = 79.</span>
Answer:
I think 1/2
Step-by-step explanation:
Since there are 4 coins overall and 2 nickels, then the probabilty is 2/4
2/4 simplified is 1/2
(I've never been too good at probability so sorry if it is wrong)
Why do you need the answer so bad? Are you trying to get a pet?
Answer:
True, the scores are not valid.
Step-by-step explanation:
The test supposed to be measuring intelligence. We can assume that the intelligence of most people relatively stable (will not change too much over a short amount of time), and can expect it should go upward with brain growth and education. But the test seems to give a huge decrease from the first and second results. Then the third result is a huge increase that even higher than the first test.
We don't know the true value of the subject, but seeing the huge gap for every repetition we can tell that the test result lacks precision.
Answer: Eleventh Grade
Step-by-step
The ratio of tenth graders to the school's total population is 86:255 = 33.7%.
The ratio of eleventh graders to the school's total population is 18:51 = 35.3%.
Since the probability of a student being in either tenth, eleventh, or twelfth grade = 1 = 100% (that is, certainty), then the probability of a randomly drawn student being in twelfth grade is (100-33.7-35.3)% = 31.0%.
When randomly choosing one student from the whole school, it is most likely (35.3%) that the student is in the eleventh grade.
Answer:
Step-by-step explanation:
<em>The probability that a point chosen at random in the given figure will be inside the larger square and outside the smaller square</em> is equal to the ratio of the area of interest to the total area:
<em>P(inside larger square and outside smaller square)</em> = area of interest / total area
<em>P(inside larger square and outside smaller square)</em> = area inside the larger square and outside the smaller square / area of the larger square
<u>Calculations:</u>
<u />
1. <u>Area inside the larger square</u>: side² = (10 cm)² = 100 cm²
2. <u>Area inside the smaller square </u>= side² = (7cm)² = 49 cm²
3. <u>Area inside the larger square and outside the smaller square</u>
- 100 cm² - 49 cm² = 51 cm²
4.<u> P (inside larger square and outside smaller squere)</u>
- 51 cm² / 100 cm² = 51/100
