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zavuch27 [327]
3 years ago
5

List the factor pairs of 186

Mathematics
1 answer:
miskamm [114]3 years ago
4 0

Answer:1, 2, 3, 6, 31, 62, 93, 186.

Step-by-step explanation:

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Researchers wanted to determine if having a DVD player in the bedroom is associated with obesity. The researchers administered a
Mashutka [201]

Answer:

is c

Step-by-step explanation:

3 0
4 years ago
Find the slope to Y = 5/2x-3
son4ous [18]

Answer:

slope = 5/2

Step-by-step explanation:

This equation is written in slope intercept form

y = mx+b where m is the slope and b is the y intercept

y = 5/2x -3

The slope is 5/2 and the y intercept is -3

5 0
4 years ago
Read 2 more answers
Find the slope and the y-intercept of the line
Rom4ik [11]

Answer:

the slope of the line is 4

m = 4

y-intercept is -8

y = 4(0) - 8 = 0 - 8 = -8

3 0
4 years ago
Part 3 - Discussion/Explanation Question
SpyIntel [72]

Step-by-step explanation:

Vertical asymptote can be Identites if there is a factor only in the denominator. This means that the function will be infinitely discounted at that point.

For example,

\frac{1}{x - 5}

Set the expression in the denominator equal to 0, because you can't divide by 0.

x - 5 = 0

x = 5

So the vertical asymptote is x=5.

Disclaimer if you see something like this

\frac{(x - 5)(x + 3)}{(x - 5)}

x=5 won't be a vertical asymptote, it will be a hole because it in the numerator and denominator.

Horizontal:

If we have a function like this

\frac{1}{x}

We can determine what happens to the y values as x gets bigger, as x gets bigger, we will get smaller answers for y values. The y values will get closer to 0 but never reach it.

Remember a constant can be represent by

a \times  {x}^{0}

For example,

1 = 1 \times  {x}^{0}

2 =  2 \times {x}^{0}

And so on,

and

x =  {x}^{1}

So our equation is basically

\frac{1 \times  {x}^{0} }{ {x}^{1} }

Look at the degrees, since the numerator has a smaller degree than the denominator, the denominator will grow larger than the numerator as x gets larger, so since the larger number is the denominator, our y values will approach 0.

So anytime, the degree of the numerator < denominator, the horizontal asymptote is x=0.

Consider the function

\frac{3 {x}^{2} }{ {x}^{2}  + 1}

As x get larger, the only thing that will matter will be the leading coefficient of the leading degree term. So as x approach infinity and negative infinity, the horizontal asymptote will the numerator of the leading coefficient/ the leading coefficient of the denominator

So in this case,

x =  \frac{3}{1}

Finally, if the numerator has a greater degree than denominator, the value of horizontal asymptote will be larger and larger such there would be no horizontal asymptote instead of a oblique asymptote.

8 0
2 years ago
Simplify: -3^2+8÷2×4-|-9|
NNADVOKAT [17]
Follow the order of operations. Evaluate absolute value first.
-3^2+8/2*4-9

Then evaluate exponents
9+8/2*4-9

Then evaluate multiplication and division from left to right
9+4*4-9
9+16-9

Then evaluate addition and subtraction from left to right
25-9
16

Final answer: 16
8 0
4 years ago
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