I don't know how to do the stuff in bold, but he made 28 out of 35 shots
Answer:
The usually speed of the bus is 50 miles/h.
Step-by-step explanation:
Let the usual speed of the bus be x mile/hour.
We know that
The bus travels 200 miles.
To reach its destination it takes time h
This week however the bus leaves at 5:40.
The bus late 40 minutes
Now the speed of the bus is = (x+10) miles/h
The new time to reach the destination is h
According to the problem,
⇒2(x²+10x)=200×10×3
⇒x²+10x = 3000
⇒x²+10x -3000=0
⇒x²+60x-50x-3000=0
⇒x(x+60)-50(x+60)=0
⇒(x+60)(x-50)=0
⇒x= -60,50
∴x=50 [since speed does not negative]
The usually speed of the bus is 50 miles/h.
Two complementary angles add up to 90 degrees. Hence, the problem can be set up and solved. Let x represents one angle and 5x represent the angle that is 5 times greater:x + 5x = 90 (simplify)6x = 90 (next divide both sides by 6 to find the value of x [the smaller angle])x = 15 (this is the smaller angle, next subtract 15 from 90 to find the greater angle)90 - 15 = 75 (this is the greater angle which is 5 times that of its complement) <span>90 take away 73...</span>