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3 years ago

Match the hydrocarbon names and structural formula : 2-butene 2-methylbutane 2-butyne

Chemistry

1 answer:

alisha [4.7K]3 years ago

3 0

2-butene - it is an alkene so it contains a double bond

2-methylbutane - it is an alkane so it contains only single bonds

2-butyne - it an alkyne so it contains a triple bond

Explanation:

You may find the structural formulas of the compounds in the attached picture.

Learn more about:

structure of organic compounds

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Imagine that you have 100g of water.

laiz [17]

Answer:

Explanation:

So, just find 55 on the solubility side and with your finger just move to the right untill you touch the line you should get in between 46-48. I would go more for 48.

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6 0

3 years ago

How many moles of nitrogen (N2) are needed to produce 9.60x10^24 molecules

Verizon [17]

The number of moles of Nitrogen : == 7.975

<h3>Further explanation </h3>

Given

9.60x10²⁴ molecules of nitrogen dioxide (NO2)

Required

The number of moles

Solution

Reaction

N2 + 2O2 → 2NO2

moles of NO2 :

= 9.6 x 10²⁴ : 6.02 x 10²³

= 15.95

From the equation, mol N2 :

= 1/2 x mol NO2

= 1/2 x 15.95

= 7.975

The number of molecules :

= 8 x 6.02 x 10²³

= 4.816 x 10²⁴

7 0

4 years ago

The pH of a 0.78M solution of 4-pyridinecarboxylic acid HC6H4NO2is measured to be 2.53.Calculate the acid dissociation constant

nika2105 [10]

Answer : The value of acid dissociation constant is, $1.1\times 10^{-5}$

Solution : Given,

Concentration pyridinecarboxylic acid = 0.78 M

pH = 2.53

First we have to calculate the hydrogen ion concentration.

$pH=-\log [H^+]$

$2.53=-\log [H^+]$

$[H^+]=2.95\times 106{-3}M$

Now we have to calculate the acid dissociation constant.

The equilibrium reaction for dissociation of (weak acid) is,

$HC_6H_4NO_2\rightleftharpoons C_6H_4NO_2^-+H^+$

initially conc. 0.78 0 0

At eqm. (0.78-x) x x

The expression of acid dissociation constant for acid is:

$k_a=\frac{[C_6H_4NO_2^-][H^+]}{[C_6H_4NO_2]}$

As, $[H^+]=[C_6H_4NO_2^-]=x$

So, $x=2.95\times 106{-3}M$

Now put all the given values in this formula ,we get:

$k_a=\frac{(x)\times (x)}{(0.78-x)}$

$k_a=\frac{(2.95\times 106{-3})\times (2.95\times 106{-3})}{(0.78-2.95\times 106{-3})}$

$K_a=1.1\times 10^{-5}$

Therefore, the value of acid dissociation constant is, $1.1\times 10^{-5}$

7 0

4 years ago

what is the molecular formula of a compound with an empiricla formula of ch and a molecular mass of 78

Dovator [93]

Answer:

C6H6

Explanation:

We can obtain the molecular formula from the empirical formula.

What we need do here is:

(CH)n = 78

The n shows the multiples of both element present in the actual compound. It can be seen that carbon and hydrogen have the same element ratio here. We then use the atomic masses of both elements to get the value of n. The atomic mass of carbon is 12 a.m.u while the atomic mass of hydrogen is 1 a.m.u

(1 + 12)n = 78

13n = 78

n = 78/13 = 6

The molecular formula is

(CH)n = (CH)6 = C6H6

6 0

4 years ago

An element has an atomic number of 22 what is the total number of valance electrons?

yuradex [85]

The Valance Electorns is 4

4 0

4 years ago