Question

Determine the bond order from the molecular electron configurations. ( σ 1 s ) 2 ( σ 1 s * ) 2 ( σ 2 s ) 2 ( σ 2 s * ) 2 ( σ 2 p ) 2 ( π 2 p ) 4 ( π 2 p * ) 2 bond order: ( σ 1 s ) 2 ( σ 1 s * ) 2 ( σ 2 s ) 2 bond order:

Answer 1

Explanation:

The bond order is defined as number of electron pairs present in a bond of the two atoms.

The formula of bond order is given by:

= $\frac{1}{2}\times (\text{Number of bonding electrons}-\text{Number of anti-bonding electrons})$

1)  $(\sigma 1 s )^2 ( \sigma 1 s*)^2 (\sigma 2s )^2 ( \sigma 2 s*)^2 ( \sigma 2 p )^2 ( \pi2 p )^4 (\pi 2 p *)^2$

Number of bonding electrons = 10

Number of anti-bonding electrons = 6

The bond order : $\frac{1}{2}\times (10-6)=2$

2) $( \sigma 1 s )^2 ( \sigma 1 s * )^2 ( \sigma 2 s )^2$

Number of bonding electrons = 4

Number of anti-bonding electrons = 2

The bond order : $\frac{1}{2}\times (4-2)=1$