Answer:
oxidation number is correct!! :)
Explanation:
Answer:
8.3334%
Explanation:
You have two masses. To find the percent of sodium chloride in water by mass, you divide the mass of NaCl by water. First, make both units the same. Easiest is to convert kg into g. 1.5kg = 1500g
125g NaCl/1500g H2O = 0.0833333333 ==> 8.3334%
Answer:
10
Explanation:
In image
Take atomic mass or molar mass
of Al =27
Answer:
- <em>The solution expected to contain the greatest number of solute particles is: </em><u>A) 1 L of 1.0 M NaCl</u>
Explanation:
The number of particles is calculated as:
a) <u>For Ionic compounds</u>:
- molarity × volume in liters × number of ions per unit formula.
b) <u>For covalent compounds</u>:
- molarity × volume in liters
The difference is a factor which is the number of particles resulting from the dissociation or ionization of one mole of the ionic compound.
So, calling M the molarity, you can write:
- # of particles = M × liters × factor
This table show the calculations for the four solutions from the list of choices:
Compound kind Particles in solution Molarity # of particles
(dissociation) (M) in 1 liter
A) NaCl ionic ions Na⁺ and Cl⁻ 1.0 1.0 × 1 × 2 = 2
B) NaCl ionic ions Na⁺ anc Cl⁻ 0.5 0.5 × 1 × 2 = 1
C) Glucose covalent molecules 0.5 0.5 × 1 × 1 = 0.5
D) Glucose covalent molecules 1.0 1.0 × 1 × 1 = 1
Therefore, the rank in increasing number of particles is for the list of solutions given is: C < B = D < A, which means that the solution expected to contain the greatest number of solute particles is the solution A) 1 L of 1.0 M NaCl.
Answer:
The concentration of the borax solution is 0.1066 M
Explanation:
Step 1: Dtaa given
Volume of a sample of aqueous borax solution = 20.00 mL = 0.020 L
Molarity of H2SO4 = 1.03 M
Volume of the H2SO4 = 2.07 mL = 0.00207 L
Step 2: The balanced equation
Na2B4O7*10H2O(borax) + H2SO4 ⇆ Na2SO4 + 4 H3BO3 + 5 H2O
Step 3: Calculate molarity of borax solution
b*Ca*Va = a * Cb*Vb
⇒with B = the coefficient of H2SO4 = 1
⇒with Ca = the concentration of borax = TO BE DETERMINED
⇒with Va = the volume of borax = 0.020 L
⇒with a = the coefficient of borax = 1
⇒with Cb = the concentration of H2SO4 = 1.03 M
⇒with Vb = the volume of H2SO4 = 0.00207 L
Ca*0.020 L = 1.03 M * 0.00207 L
Ca = (1.03 * 0.00207) / 0.020
Ca = 0.1066 M
The concentration of the borax solution is 0.1066 M