I need help doing this can somebody please help?! It’s number 2.

Use the box method to distribute and simplify (-5x-2)(-2x^2+6x).

Mkey [24]

Answer:

$10x^{3} - 26x^{2} - 12x$

Step-by-step explanation:

1) Use the FOIL method: (a+b)(c+d)=ac+ad+bc+bd.

$10x^{3} - 30x^{2} + 4x^{2} -12x$

2) Collect like terms.

$10x^{3} + (-30x^{2} +4x^{2} )-12x$

3) Simplify.

$10x^{3} - 26x^{2} -12x$

Therefor, the answer is, 10x^3 - 26x^2 - 12x.

3 0

2 years ago

Can someone please help

bija089 [108]

Answer:

answer is 1 x( x-4) ok to mmma abhi tak school ki chuti h or bina kisi ne bhi roka aur wo phle h to time but only a few days after lady Catherine visit the gentleman arrived early in the given it most unwillingly

6 0

3 years ago

What value ofx is in the solution set of 3(x-4)>5x +2?

kvv77 [185]

$\boldsymbol{\sf{3(x-4) > 5x +2 }}$

Use the distributive property to multiply 3 by x−4.

$\boldsymbol{\sf{3x-12 > 5x+2 }}$

Subtract 5x on both sides.

$\boldsymbol{\sf{3x-12-5x > 2 } }$

Combine 3x and −5x to get −2x.

$\boldsymbol{\sf{-2x-12 > 2 }}$

Add 12 to both sides.

$\boldsymbol{\sf{-2x > 2+12 \ \longmapsto \ \ [Add \ 2 +12]}}$

$\boldsymbol{\sf{-2x > 14}}$

Divide both sides by −2. Since −2 is < 0, the inequality direction is changed.

$\boldsymbol{\sf{x < \dfrac{14}{-2} \ \ \longmapsto \ \ \ [Split]}}$

$\boxed{\boldsymbol{\sf{x < -7 }}}$

So in the <u>inequality 3(x-4)>5x +2</u>, the value of x is -7.

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8 0

1 year ago

Given a population with a mean of muμequals=100100 and a variance of sigma squaredσ2equals=3636, the central limit theorem appl

lakkis [162]

Answer:

a) $\bar X \sim N(100,\frac{6}{\sqrt{25}}=1.2)$

$\mu_{\bar X}=100$ $\sigma^2_{\bar X}=1$

b) $P(\bar X >101)=1-P(\bar X$

c) $P(\bar X$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

The complement rule is a theorem that provides a connection between the probability of an event and the probability of the complement of the event. Lat A the event of interest and A' the complement. The rule is defined by: $P(A)+P(A') =1$