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Mrac [35]
2 years ago
7

Use the box method to distribute and simplify (-5x-2)(-2x^2+6x).

Mathematics
1 answer:
Mkey [24]2 years ago
3 0

Answer:

10x^{3} - 26x^{2} - 12x

Step-by-step explanation:

1)  Use the FOIL method: (a+b)(c+d)=ac+ad+bc+bd.

10x^{3} - 30x^{2} + 4x^{2} -12x

2)  Collect like terms.

10x^{3} + (-30x^{2} +4x^{2} )-12x

3) Simplify.

10x^{3} - 26x^{2} -12x

Therefor, the answer is, 10x^3 - 26x^2 - 12x.

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4 0
3 years ago
If you are dealt 4 cards from a shuffled deck of 52​ cards, find the probability that all 4 cards are diamonds
diamong [38]
Probability=13/52*12/51*11/50*10/49=11/4165
4 0
3 years ago
The sum of two numbers is 56, and their difference is 10. What are the numbers?
Elanso [62]

Answer:

23 and 33

Step-by-step explanation:

23+33=56

33-23=10

6 0
3 years ago
Read 2 more answers
For a school play, 739 tickets valued at $857 were sold. Some cost $1 and others cost a $1.50. How many $1 tickets were sold?
balu736 [363]

Answer:

503 $1 tickets sold.

Step-by-step explanation:

Use two equations  

Let x = number of $1 tickets sold  

Let y = number of $1.50 tickets sold  

x + y = 739  

1x + (1.5)y = 857  

First equation ==> y = 739 - x  

Plug this into the second equation  

x + (1.5)(739 - x) = 857  

x + 1108.5 - 1.5x = 857  

- 0.5x = -251.5  

x = 503  

There were 503 $1 tickets sold.  

To find the number of $1.50 tickets, just plug this value of x into either one of the equations.  

(503) + y = 739       (739 - 503 = 236)

y = 236  

There were 236 $1.50 tickets sold.

3 0
3 years ago
Amira is solving this problem.
Strike441 [17]
I think its B im pretty sure feel free to mark me brainlyest it would mean alot. Hope this helped!
7 0
3 years ago
Read 2 more answers
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