All categories

2 years ago

What value ofx is in the solution set of 3(x-4)>5x +2?

Mathematics

1 answer:

kvv77 [185]2 years ago

8 0

$\boldsymbol{\sf{3(x-4) > 5x +2 }}$

Use the distributive property to multiply 3 by x−4.

$\boldsymbol{\sf{3x-12 > 5x+2 }}$

Subtract 5x on both sides.

$\boldsymbol{\sf{3x-12-5x > 2 } }$

Combine 3x and −5x to get −2x.

$\boldsymbol{\sf{-2x-12 > 2 }}$

Add 12 to both sides.

$\boldsymbol{\sf{-2x > 2+12 \ \longmapsto \ \ [Add \ 2 +12]}}$

$\boldsymbol{\sf{-2x > 14}}$

Divide both sides by −2. Since −2 is < 0, the inequality direction is changed.

$\boldsymbol{\sf{x < \dfrac{14}{-2} \ \ \longmapsto \ \ \ [Split]}}$

$\boxed{\boldsymbol{\sf{x < -7 }}}$

So in the inequality 3(x-4)>5x +2, the value of x is -7.

ヘ( ^o^)ノ＼(^_^ )If you want to learn more about mathematics, I share this link to complement your learning:

brainly.com/question/17070130

You might be interested in

1 question geometry, thanks :)

Yuri [45]

Point B is located at (-6, 5)

Multiply each coordinate by the scale factor 3 to get

-6*3 = -18

5*3 = 15

The point B' is located at (-18, 15)

3 0

3 years ago

A savings account compounds interest, at a rate of 25% once a year. Eve puts 500 in the account as the principal. How can eve se

Alekssandra [29.7K]

F(x) = 500(1.25)^x would be the function

8 0

3 years ago

Read 2 more answers

I can’t figure out how to use the zeros in the polynomial. Please explain

Temka [501]

Answer:

a) $P (x) = (x + 3) (x-1) (x-4)$

b) $P (x) = (2x + 5) (5x - 4) (x-6)$

c) $P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2$

Step-by-step explanation:

For the question a * you need to find a polynomial of degree 3 with zeros in -3, 1 and 4.

This means that the polynomial P(x) must be zero when x = -3, x = 1 and x = 4.

Then write the polynomial in factored form.

$P (x) = (x + 3) (x-1) (x-4)$

Note that this polynomial has degree 3 and is zero at x = -3, x = 1 and x = 4.

For question b, do the same procedure.

Degree: 3

Zeros: -5/2, 4/5, 6.

The factors are

$x = -\frac{5}{2}\\\\x +\frac{5}{2} = 0\\\\(2x +5) = 0$

---------------------------------------

$x =\frac{4}{5}\\\\x-\frac{4}{5} = 0\\\\(5x-4) = 0$

--------------------------------------

$x = 6\\\\(x-6) = 0$

--------------------------------------

$P (x) = (2x + 5) (5x - 4) (x-6)$

Finally for the question c we have

Degree: 5

Zeros: -3, 1, 4, -1

Multiplicity 2 in -1

$x = -3\\\\(x-3) = 0$

--------------------------------------

$x = 1\\\\(x-1) = 0$

--------------------------------------

$x = 4\\\\(x-4) = 0$

----------------------------------------

$x = -1\\\\(x + 1) = 0$

-----------------------------------------

$P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2$

8 0

3 years ago

If, for all x, f'(x)=(x-2)^4(x-1)^3, it follows that funtaion f has

Elenna [48]

Answer:

We say that f(x) has an absolute (or global) minimum at x=c if f(x)≥f(c) f ( x ) ≥ f ( c ) for every x in the domain we are working on. We say that f(x) has a relative (or local) minimum at x=c iff(x)≥f(c) f ( x ) ≥ f ( c ) for every x in some open interval around x=c .

4 0

3 years ago

Y = Â¼ x and y=Â¼x - 5. explain how the graphs are the same and how they are different

emmasim [6.3K]

Do you still need help with this if so graphes have a bigger letter and a smaller letter

3 0

3 years ago