For compounding interests, we use the equation F = P (1+i)^n where F is the future amount of the principal amount, P, in n years. Take note that the interest to be used should be the effective interest rate. In this case, it is already the effective interest rate.
F = P (1+i)^n
F = $4000 (1+.055)^4
F = $4955.2986
Given problem;
A =
r²
Solve for π;
To solve for π implies that we make it the subject of the expression.
So;
A = π r²
Now multiply both sides by 
So;
A x
=
x r² x
r² cancels out from the right side and leaves only π;
π = 
So 
3i (- 1 + 2i) Remove the brackets.
3i (-1) + (2i)(3i) Look at the first set of brackets around the -1
-3i + 6i^2 But i^2 = - 1[ I hope that's the way you are using it]
-3i - 6 or -6 - 3i or -3(2 - i) <<<<< answer
48.4 hope you get it correct!
Answer:
71701,71702, 71703 etc
Step-by-step explanation:
Given :
×
and 8.17×
Now
×
=71700 and
8.17×
=817000
There are so many numbers between 71700 and 817000
Like: 71701,71702, 71703 etc