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3 years ago

A ball is projected into the air. Where is potential energy the greatest?

Chemistry

1 answer:

Alla [95]3 years ago

5 0

B) B. is the point where it has maximum potential energy.

Explanation:

This an example of projectile motion.
In projectile motion, the path of an object is illustrated in the picture given. In the given picture, the minimum kinetic energy and the maximum potential energy is at B
B is the point where the object, for example, the ball is reaching its point of minimum kinetic energy which means that after this point the object's downward motion starts.
Hence, the transition from the upward motion to the downward motion is the point where it has the maximum potential energy.

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How many electrons are in O2-?

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There will be 16 electrons in O2-

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Name the only satellite which is known to have an atmosphere in the planet it orbits

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Answer:

Titan which orbits Saturn

Explanation:

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3 years ago

For the readion 2Na + Ch> 2NaCl, how many grams of Ch are required to read completely with 450 g Na

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3 years ago

Butane (C4H10) has a heat of vaporization of 22.44 kJ/mol and a normal boiling point of -0.4 ∘C. A 250 mL sealed flask contains

erastova [34]

Given that:

The heat of vaporization = 22.44 kJ/mol = 22440 J/mol
normal boiling point which is the initial temperature = 0.4° C = (273 + (-0.4))K = 272.6 K
volume = 250 mL = 0.250 L
Mass of butane = 0.8 g
the final temperature = -22° C = (273 + (-22)) K = 251 K

The first step is to determine the vapor pressure at the final temperature of 251K by using the Clausius-Clapeyron equation. This is following by using the ideal gas equation to determine the numbers of moles of butane gas. After that, the mass of butane present in the liquid is determined by using the relation for the number of moles.

Using Clausius-Clapeyron Equation:

$\mathbf{In (\dfrac{P_2}{P_1} )= -\dfrac{\Delta H_{vap}}{R}(\dfrac{1}{T_2} - \dfrac{1}{T_1})}$

where;

P1 and P2 correspond to the temperature at T1 and T2.

∴

replacing the values into the given equation, we have;

$\mathbf{In \dfrac{P_2}{1\ atm} = -\dfrac{22440 \ J/mol}{8.314 \ J/mol.K}(\dfrac{1}{251 \ K} - \dfrac{1}{272.6 \ K})}$

$\mathbf{In \dfrac{P_2}{1\ atm} =-(0.852053785)}$

$\mathbf{P_2=0.427 \ atm}$

As such, at -22° C; the vapor pressure = 0.427 atm

Now, using the ideal gas equation:

PV = nRT

where:

P = Pressure
V = volume
n = number of moles of butane
R = universal gas constant
T = temperature

∴

Making (n) the subject of the formula:

$\mathbf{n = \dfrac{PV}{RT}}$

$\mathbf{n = \dfrac{0.427 atm \times 0.250 L}{(0.08206 \ L.atm/k.mol) \times 251}}$

$\mathbf{n =0.00518 mol}$

We all know that the standard molecular weight of butane = 58.12 g/mol

∴

Using the relation for the number of moles which is:

$\mathbf{number \ of \ moles = \dfrac{mass}{molar mass}}$

mass = 0.00518 mole × 58.12 g/mol

mass = 0.301 g

∴

The mass of butane in the flask = 0.301 g

But the mass of the butane present as a liquid in the flask is

= 0.8 g - 0.301 g

= 0.499 g

In conclusion, the mass of the butane present as a liquid in the flask is 0.499 g

Learn more about vapourization here:

brainly.com/question/17039550?referrer=searchResults

7 0

3 years ago

How many electrons are needed to equal the mass of a proton?

charle [14.2K]

<span>How many electrons are needed to equal the mass of a proton?
</span>
The correct answer is that you need 1836 electron to equal the mass of a proton. This means that a proton is equals to 1836 electron or 1 = 1836. This is the answer to your question. I hope this answer helped you.

5 0

4 years ago