Answer:
the last one: all three are examples of Newton's laws
Explanation:
i guess
Ernest Rutherford's gold foil experiment was when he shot positively charged particles at a thin layer of gold foil. He concluded that there was a core that contained most of the atom's mass, the core is the nucleus
Answer:
pH = 7.01
Explanation:
The pH can be calculated using the formula:
pH = -log[H⁺]
In this formula, [H⁺] represents the concentration of H⁺. Since you have been given this value, you can easily find the pH.
pH = -log[H⁺]
pH = -log[9.71 x 10⁻⁸]
pH = 7.01
The required pressure of the gas is 546 mmHg.
<h3>What is the relation between volume and pressure?</h3>
Relation between the volume and pressure of gas is explained through the ideal gas equation PV = nRT, and for the question required equation is:
P₁V₁ = P₂V₂, where
P₁ & V₁ are the initial pressure and volume.
P₂ & V₂ are the final pressure and volume.
On putting values from the question to the equation, we get
P₂ = (780)(350) / (500) =
P₂ = 546 mmHg
Hence required pressure is 546 mmHg.
To know more about ideal gas equation, visit the below link:
brainly.com/question/24236411
#SPJ1
Answer:
The hot tea should transfer <em>25.63 kJ</em> the surroundings to cool the tea.
Explanation:
- To solve this problem, we can use the relation:
<em>Q = m.c.ΔT,</em>
where, Q is the amount of heat has to be transferred from the tea to the surroundings to cool the tea (Q = ??? J).
m is the mass of the hot tea (m = dV = (1.0 g/mL)(250 mL) = 250 g), suppose the density of water is the density of tea.
c is the specific heat of the hot tea (c = 4.10 J/°C.g).
ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = 350 K - 375 K = -25°C).
<em>∴ Q = m.c.ΔT</em> = (250 g)(4.10 J/°C.g)(-25°C)) = <em>- 25630 J = - 25.63 kJ.</em>
<em>So, the hot tea should transfer 25.63 kJ the surroundings to cool the tea.</em>
