Let us make a list of all the details we have
We are given
The cost of each solid chocolate truffle = s
The cost of each cream centre chocolate truffle = c
The cos to each chocolate truffle with nuts = n
The first type of sweet box that contains 5 each of the three types of chocolate truffle costs $41.25
That is 5s+5c+5n = 41.25 (cost of each type of truffle multiplied by their respective costs and all added together)
The second type of sweet box that contains 10 solid chocolate trufles, 5 cream centre truffles and 10 chocolate truffles with nuts cost $68.75
That is 10s+5c+10n = $68.75
The third type of sweet box that contains 24 truffles evenly divided that is 12 each of solid chocolate truffle and chocolate truffle with nuts cost $66.00
That is 12s+12n=$66.00
Hence option C is the right set of equations that will help us solve the values of each chocolate truffle.
Answer:
(x - 7)² + (y + 2)² = (2√13)²
Step-by-step explanation:
We already know that the center is at (7, -2), but must find the radius. The radius is the distance between the points (7, -2) and (1, -6):
r = √ [6² + 4²] ) = √(36 + 16) = √52 = √4√13 = 2√13.
Then the desired equation is (x - 7)² + (y + 2)² = (2√13)²
Answer:
The answer is A) 379.9
Step-by-step explanation:
3.14(11^2)
3.14*11^2
3.14*(11*11)
379.94 if rounded to the nearest tenth it would be 379.9
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