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siniylev [52]
3 years ago
6

True or false? A theorem is a statement that can be easily proved using a

Mathematics
1 answer:
dedylja [7]3 years ago
6 0
???why did you say the question and then answer it
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Which of the following is a solution to 2cos x + 1 = 0? 60° 120° 210° 300°
klasskru [66]
Rewrite   <span>2cos x + 1 = 0    as:

2 cos x = -1, and then cos x = -1/2

x must be in Quadrant II or Quadrant III, since the adj. side is negative.

Note that the angle 120 has adj. side -1 and hyp 2.  So 120 degrees is one solution.  

Now what about a possible 2nd solution, to be found in Quadrant III?  That would be -120 degrees, which has the same terminal line as does 240 degrees.

No soap.

So, the solution is 120 degrees.</span>
6 0
3 years ago
Read 2 more answers
Over the last week,the daily low temperatures in degrees Fahrenheit have been -4,6.2,18 1/2,-5.9,21,-1/4,1.75.List these numbers
Anit [1.1K]

-5.9, -4.6, -1/4, 1/2, 1.75, 2, 18, 21.

8 0
3 years ago
Solve the equation x2<br> 18x + 21 = -3x to the nearest tenth.
Bumek [7]

Answer:

1x=-29

2x=-1

Step-by-step explanation:

i hope its useful.

7 0
2 years ago
15 inches and 8 feet in the simplest form
aivan3 [116]
9ft n 3 inches , because 12 inches is a feet ! if you know then you know
5 0
3 years ago
The sum of the ages of Berma, her mother Rinna and her father Erwin is 80. Two years from now, Rinna’s age will be 13 less than
jekas [21]

Answer: Berma is 5 years old

Rinna is 38 years old

Erwin is 37 years old

Step-by-step explanation:

Let x represent Berma's age

Let y represent Rinna's age

Let z represent Erwin's age

Since the sum of their ages is 80,

x + y + z = 80 - - - - - - -1

Two years from now, Rinna’s age will be 13 less than the sum of Erwin’s age and twice Berma’s age. This means that

y +2 = [ (z+2) + 2(x+2) ] - 13

y +2 = z + 2 + 2x + 4 - 13

2x - y + z = 13 + 2 - 4 -2

2x - y + z = 9 - - - - - - -2

Three years ago, 15 times Berma’s age was 5 less than the age of Rinna. It means that

15(x - 3) = (y - 3) - 5

15x - 45 = y - 3 - 5

15x - y = - 8 + 45

15x - y = 37 - - - - - - - -3

From equation 3, y = 15x - 37

Substituting y = 15x - 37 into equation 1 and equation 2, it becomes

x + 15x - 37 + z = 80

16x + z = 80 + 37 = 117 - - - - - - 4

2x - 15x + 37 + z = 9

-13x + 2 = -28 - - - - - - - - -5

subtracting equation 5 from equation 4,

29x = 145

x = 145/29 = 5

y = 15x - 37

y = 15×5 -37

y = 38

Substituting x= 5 and y = 38 into equation 1, it becomes

5 + 38 + z = 80

z = 80 - 43

z = 37

6 0
3 years ago
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