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Olenka [21]
3 years ago
8

Whats the solution to the system of inequalities? -3x-y+z=6 -3x-y+3z=0 -3z=3

Mathematics
1 answer:
Naya [18.7K]3 years ago
3 0

Answer:

  This system of equations has <em>no solution</em>. It is inconsistent.

Step-by-step explanation:

The last equation tells you z = -1.

Substituting this value for z in the other two equations allows them to be written as ...

  -3x -y = 7

  -3x -y = 3

There are no values of x and y that can make both these equations true.

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Evaluate b²c¹ for b=8 c=-4
AVprozaik [17]

Answer:

The answer is -256.

Step-by-step explanation:

You have to substitute the value of b and c into the expression :

{b}^{2}  {c}^{1}

Let b = 8,

Let c = -4,

{8}^{2}  \times  { - 4}^{1}

= 64 \times  - 4

=  - 256

8 0
3 years ago
Help me please I need the help
serious [3.7K]

Answer:

p - 3

Step-by-step explanation:

Key expression: 3 fewer than

Fewer than = subtract from

subtract 3 from a number, p

This means that the expression would be p - 3

Because you are subtracting 3 from a number ( p )

5 0
3 years ago
Please answer the question from the attachment.
bezimeni [28]
Look at the cars mpg (miles per gallon) then multiple it by 15
7 0
3 years ago
Enter the equation of the line meeting the given conditions. Please put the equation instandard form.
just olya [345]

first, the slope is needed, which is 3-2/3--3 which is 1/6 and so this will be y=(1/6)x+b which then we'll input (3,3) which is 3=2+b or b=1 so the equation is y=(1/6)x+1

6 0
2 years ago
(3x-5)/(x-5)&gt;=0 <br> How do I get the answers for this problem?
Diano4ka-milaya [45]
\frac{3x-5}{x-5} > 0 

First, note that x is undefined at 5. / x ≠ 5
Second, replace the inequality sign with an equal sign so that we can solve it like a normal equation. / Your problem should look like: \frac{3x-5}{x-5} = 0
Third, multiply both sides by x - 5. / Your problem should look like: 3x - 5 = 0
Forth, add 5 to both sides. / Your problem should look like: 3x = 5
Fifth, divide both sides by 3. / Your problem should look like: x = \frac{5}{3}
Sixth, from the values of x above, we have these 3 intervals to test: 
x < \frac{5}{3}
\frac{5}{3} < x < 5
x > 5
Seventh, pick a test point for each interval. 

1. For the interval x < \frac{5}{3} :
Let's pick x - 0. Then, \frac{3x0-5}{0-5} > 0
After simplifying, we get 1 > 0 which is true.
Keep this interval.

2. For the interval \frac{5}{3} < x < 5:
Let's pick x = 2. Then, \frac{3x2-5}{2-5} > 0
After simplifying, we get -0.3333 > 0, which is false.
Drop this interval.

3. For the interval x > 5:
Let's pick x = 6. Then, \frac{3x6-5}{6-5} > 0
After simplifying, we get 13 > 0, which is ture.
Keep this interval.
Eighth, therefore, x < \frac{5}{3} and x > 5

Answer: x < \frac{5}{3} and x > 5

3 0
3 years ago
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