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Elden [556K]
3 years ago
12

6х + Зу = 15 What is the ordered pair?

Mathematics
1 answer:
11111nata11111 [884]3 years ago
3 0
The answer for 6x + 3y = 15 is should be x= -1/2 y+5/2
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2x+y=3<br>x-y= 1<br><br>solve the equation ​
svetlana [45]

Answer:

x = 4/3

y = 1/3

Step-by-step explanation:

System of equations! This is set up really well to make the second equation equal x then substitute.

x - y = 1

x = 1 + y

and then our substitution:

2 (1+y) + y = 3

and solve:

2 + 2y + y = 3

3y + 2 = 3

3y = 1

y = 1/3

And now we can substitute that value into one of our equations:

x - (1/3) = 1

x = 4/3

Next we should check by substituting these values into both of our equations:

2 (4/3) + (1/3) = 3

9 / 3 does equal 3 !

(4/3) - (1/3) does equal 1 !

Therefore, x = 4/3 , and y = 1/3

4 0
3 years ago
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The Vega family has a three yourself own contract mark Vegas is the family gets a total of 3×10 to the fourth minutes of talk ti
Over [174]
120 minutes of talk time and share
4 0
4 years ago
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Can anyone help me?.....
AveGali [126]
\bf \textit{so there are }2\frac{7}{9}\textit{ sections of land each one is }2\frac{1}{5}

how much land are they all in total?  well, is just their product.

let's firstly convert the mixed fractions to "improper" and then multiply.

\bf \stackrel{mixed}{2\frac{7}{9}}\implies \cfrac{2\cdot 9+7}{9}\implies \stackrel{improper}{\cfrac{25}{9}}&#10;\\\\\\&#10;\stackrel{mixed}{2\frac{1}{5}}\implies \cfrac{2\cdot 5+1}{5}\implies \stackrel{improper}{\cfrac{11}{5}}&#10;\\\\\\&#10;\cfrac{25}{9}\cdot \cfrac{11}{5}\implies \cfrac{25}{5}\cdot \cfrac{11}{9}\implies \cfrac{5}{1}\cdot \cfrac{11}{9}\implies \cfrac{55}{9}\implies 6\frac{1}{9}
7 0
3 years ago
Read 2 more answers
What’s the next number in this sequence
Black_prince [1.1K]

Answer:

There is a possibility it could be 23, but I am probably wrong

Step-by-step explanation:

7 0
3 years ago
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34.7% of city employees ride the bus to work. Last year, 5.2% of city employees rode the bus to work. What is the relative chang
DaniilM [7]

Answer:

5.67\%

Step-by-step explanation:

The relative change is defined by the following equation:

Relative\hspace{3}change=\frac{x-x_r_e_f_e_r_e_n_c_e}{x_r_e_f_e_r_e_n_c_e}   (1)

Where:

x=Value\hspace{3}of\hspace{3}indicator\hspace{3}in\hspace{3}period\hspace{3}2

x_r_e_f_e_r_e_n_c_e=Value\hspace{3}of\hspace{3}indicator\hspace{3}in\hspace{3}period\hspace{3}1

With this in mind, let's replace the values in the equation (1):

Relative\hspace{3}change=\frac{34.7-5.2}{5.2}=\frac{29.5}{5.2}=5.673076923\approx5.67\%

4 0
3 years ago
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