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xenn [34]
3 years ago
7

Mr. Smith plans to serve 200 hamburgers at the company picnic. How many packages of hamburger buns will he need if buns come in

packages of 12? How many packages will he need if buns come in packages of 16?
Mathematics
1 answer:
meriva3 years ago
8 0

Answer:

34 packages

25 packages

Step-by-step explanation:

He needs a pair of buns for each hamburger.

He needs 200 hamburger. That means that he needs 400 buns for his picnic.

If buns come in a package of 12, the number of packages he needs is:

400 / 12 = 33.33 packages

Because packages come in whole numbers, we have to round up.

That means he needs 34 packages.

If buns come in a package of 16, the number of packages he needs is:

400 / 16 = 25 packages

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If h(x) = x - 7 and g(x) = x2, which expression is equivalent to (g0h)(5)?
notsponge [240]

Answer:

A

Step-by-step explanation:

I honestly couldn't tell you how to do this, I don't understand it. I just took the test and got this question correct. The answer is A, (5-7)^2.

6 0
3 years ago
The current population of a town is 10,000 and its growth in years can be represented by P(t) = 10,000(0.2)^t, where t is the ti
DiKsa [7]

Answer:

1) 20%

2) Choice a.

Step-by-step explanation:

P(t)=10000(0.2)^t

1) P(0) is the population initially.

P(1) is the population after a year.

\frac{P(1)}{P(0)} represents the population increase factor.

So let's evaluate that fraction:

\frac{P(1)}{P(0)}

\frac{10000(0.2)^1}{10000(0.2)^0}

\frac{0.2^1}{0.2^0}=\frac{0.2}{1}=0.2

0.2=20%

2) Let's figure out the population growth in terms of months instead of years.

P(t)=10000(0.2)^{t}

We want t to represent months.

A full year is 12 months, in a full year we have that P(1)=10000(0.2)^1=10000(0.2)=2000

So we want a new P such that P(12)=2000 since 12 months equals a year.

Let's look at the functions given to see which gives us this:

a) P(12)=10000(0.87449)^{12}=2000 \text{approximately}

b) P(12)=10000(0.87449)^{12(12)}=0 \text{ approximately}

c) P(12)=10000(0.87449)^{\frac{1}{12}}=9889 \text{approximately}

d) P(12)=10000(0.87449)^{12+12}=400 \text{approximately}

So a is the function we want.

Also another way to look at this:

P(t)=10000(.2)^t where t is in years.

P(t)=10000(.2^\frac{1}{12})^t where t is in months.

And .2^\frac{1}{12}=0.874485 \text{approximately}

8 0
3 years ago
Suppose that an object whose is 10th weighs 50 N find the weight of an object whose is 6 kg
Nady [450]
Weight is another term for the force from mass multiplied by acceleration due to gravity, the equation being expressed as f = ma, being force, mass, and acceleration respectively.

We already have 2 parts of the equation,50 = 10a 

Acceleration due to gravity on the planet is 5 m/s^2

Plug it into the equation f = ma

f=6kg x 5m/s^2

Weight or force from gravity is 60N.

8 0
3 years ago
Helppp please I have limited time
Sophie [7]

Answer:

p = <u>T</u> - a - <u>b</u>

Step-by-step explanation:

Hope that helps, not sure if it is correct though.

7 0
3 years ago
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ExtremeBDS [4]
A. 8 cats per week. if you simplify 40/5, it equals 8/1
7 0
3 years ago
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