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2 years ago

5

Find the value of x.

1 answer:

sveticcg [70]2 years ago

7 0

If 98 - 32 = 66,

then x = 66°

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Use the drawing tool(s) to form the correct answer on the provided graph.

Kitty [74]

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

$y> \frac{1}{4}x+6$ ------>inequality A

The solution of the inequality A is the shaded area above the dashed line $y=\frac{1}{4}x+6$

The y-intercept of the dashed line is (0,6)

The x-intercept of the dashed line is (-24,0)

The slope of the dashed line is positive m=1/4

$y> 2x-1$ ------>inequality B

The solution of the inequality B is the shaded area above the dashed line $y=2x-1$

The y-intercept of the dashed line is (0,-1)

The x-intercept of the dashed line is (0.5,0)

The slope of the dashed line is positive m=2

The solution of the system of inequalities is the shaded area between the two dashed lines

using a graphing tool

see the attached figure

4 0

2 years ago

What is the inverse of function F f(x) 3-x/7

algol [13]

Answer: f^-1(x)=-7x+3 maybe ? i think

Step-by-step explanation:

8 0

2 years ago

Find all angles, 0 ≤C<360 that satisfy the equation below, to the nearest tenth of a degree.

ludmilkaskok [199]

Move all the terms involving the sine to one side, and all the numbers to the other:

$9\sin(c)-2=\sin(c)-7 \iff 8\sin(c) = -5\iff \sin(c)=-\dfrac{5}{8} \iff c = \arcsin\left(-\dfrac{5}{8}\right)\approx 321.3$

7 0

3 years ago

Iris charges a fee for her consulting services plus an hourly rate that is 1 1/5 times her fee. On a 7-hour job, Iris charged $4

Kryger [21]

470/7= 67.14......

67.14 was her fee

67.14 * 1.5 = 100.71

100.71 is her hourly rate

8 0

3 years ago

On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th

Elena L [17]

Answer:

The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, a = $\sqrt{(3-0)^{2}+(4-0)^{2}}$

Or, a = $\sqrt{9+16}$

Or, a = $\sqrt{25}$

∴ a = 5 unit

Similarly

The measure of length BC = b = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, b = $\sqrt{(3-3)^{2}+(2-4)^{2}}$

Or, a = $\sqrt{0+4}$

Or, b = $\sqrt{4}$

∴ b = 2 unit

And

So, The measure of length CA = c = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, c = $\sqrt{(3-0)^{2}+(2-0)^{2}}$

Or, c = $\sqrt{9+4}$

Or, c = $\sqrt{13}$

∴ c = $\sqrt{13}$ unit

Now, area of Triangle written as , from Heron's formula

A = $\sqrt{s\times (s-a)\times (s-b)\times (s-c)}$

and s = $\frac{a+b+c}{2}$

I.e s = $\frac{5+2+\sqrt{13}}{2}$

Or. s = $\frac{7+\sqrt{13}}{2}$

So, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}$

Or, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}$

Or, A = $\frac{3}{2}$ × $\sqrt{1+\sqrt{13} }$

∴ Area of triangle = 1.5 $\sqrt{4.6}$

Hence The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$ Answer

7 0

3 years ago

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