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faltersainse [42]
4 years ago
7

Use the diagram to complete the statement. m angle ECD=

Mathematics
1 answer:
eimsori [14]4 years ago
7 0

Answer:

angle ECD = 72

Step-by-step explanation:

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evablogger [386]

Answer:

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Step-by-step explanation:

4 0
3 years ago
if alisson worked the times in the table and makes $9.32 an hour, how much was her gross pay this week
LenaWriter [7]
Hrs worked = 9.25 + 8.75 + 9 + 8.25 + 9 = 44.25 hrs. (44.25 - 40 = 4.25 hrs overtime) 
<span>40 hrs * $9.32 = $372.80 (Straight time) </span>

<span>$9.32 * 1.5 = $13.98 (Overtime rate) </span>
<span>4.25 (Overtime hrs.) x $13.98 (Overtime rate) = $59.42 (Overtime pay) </span>

<span>$372.80 + $59.42 = $432.22 (Total gross pay)</span>
4 0
3 years ago
Find sin(x/2), cos(x/2), and tan(x/2) from the given information.
Nimfa-mama [501]

The values of sin (x/2) = 4/√17,   cos (x/2) = 1/√17 and  tan (x/2) = 4.

<h3>What is Trigonometry?</h3>

Trigonometric ratios are the ratios of the length of sides of a triangle. These ratios in trigonometry relate the ratio of sides of a right triangle to the respective angle.

Here, cos x = -15/17  (given)

we know, cos x = 2cos²x/2 - 1

                cos²(x/2) = (cos x + 1)/2

                  cos²(x/2) = (-15/17 + 1)/2

                 cos²(x/2) = 1/17

                 cos (x/2) = 1/√17

then, sin (x/2) = √(1- cos²(x/2))  

          sin (x/2) = √(1 - 1/17)

          sin (x/2) = √16/17

          sin (x/2) = 4/√17

and tan (x/2) = sin (x/2) / cos (x/2)  

       tan (x/2) = \frac{4/\sqrt{17} }{1/\sqrt{17} }

       tan (x/2) = 4

Thus, the values of sin (x/2) = 4/√17,   cos (x/2) = 1/√17 and  tan (x/2) = 4.

Learn more about Trigonometry from:

brainly.com/question/22698523

#SPJ1

6 0
2 years ago
What is 25 more than 50 as an expression
lesya [120]

Answer:75

Step-by-step explanation: 50 + 25

3 0
4 years ago
Read 2 more answers
What quadratic function does the graph represent?
nekit [7.7K]

Answer:

f(x)=-\frac{1}{3}(x-2)^2+4,

Step-by-step explanation:

The function of the graph can be written in the vertex form as

f(x)=a(x-h)^2+k, where V(h,k)=V(2,4) is the vertex of the quadratic function.

We substitute the value to obtain;

f(x)=a(x-2)^2+4,

The point (5,1) lies on the graph so we use it to determine the value of a.

1=a(5-2)^2+4,

1-4=a(3)^2,

-3=9a,

a=-\frac{1}{3}

The required equation is

f(x)=-\frac{1}{3}(x-2)^2+4,

5 0
3 years ago
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