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2 years ago

I need help please help

Mathematics

1 answer:

Vedmedyk [2.9K]2 years ago

8 0

Answer:

$m(x)=x^4-x^3+8x-1\\\\n(x)=|x+6|$

Are not one-to-one functions

Step-by-step explanation:

As m(x) has symmetry at the line x=0, it is not one-to-one

As n(x) has symmetry at the line x=-6, it is not one-to-one

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Jack's lunch at a restaurant costs $13.00, without tax. He leaves the waiter a 17% tip of the cost of the lunch. What is the tip

dusya [7]

Answer:

$2.21

Step-by-step explanation:

Given data

Cost = $13.00

Tip= 17%

Let us find the amount of the tip

=17/100*13

=0.17*13

=$2.21

Hence the tip is $2.21

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2 years ago

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user100 [1]

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3 years ago

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Find two positive numbers satisfying the given requirements. the product is 242 and the sum is a minimum. (smaller value) (large

Pepsi [2]

The two positive numbers satisfying the given requirements are 15.56 and 15.56

For given question,

Let x and y be two positive numbers satisfying the given requirements.

⇒ xy = 242 .............(1)

The sum of given two positive numbers is a minimum.

Let the sum of given two positive numbers is S.

⇒ x + y = S ............(2)

From equation(1),

⇒ y = 242/x

Substitute above value of y in equation (2),

⇒ x + y = S

⇒ S = x + (242 / x)

Now, for above equation we find the derivative of x with respect to x.

⇒ 0 = 1 - $\frac{242}{x^{2} }$

⇒ 242/x² = 1

⇒ x² = 242

⇒ x = ±15.56

Since the numbers are positive, x = 15.56

For x = 15.56

⇒ y = 15.56

Therefore, the two positive numbers satisfying the given requirements are 15.56 and 15.56

Learn more about the equation here:

brainly.com/question/649785

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1 year ago

Evaluate 7-5p+3q when p=1 and q=7

KIM [24]

Answer:

Step-by-step explanation:

Since it gives you the values of p and q, just plug it into the expression:

7 - 5p + 3q

7 - 5(1) + 3(7)

7 - 5 + 21

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2 years ago

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Let f(x)=4-x^2, find ( f(x+h)-f(x) ) / h and simplify

Alja [10]

If $f(x)=4-x^2$ , then

$f(x+h)=4-(x+h)^2=4-(x^2+2xh+h^2)=4-x^2-2xh-h^2$

$\dfrac{f(x+h)-f(x)}h=\dfrac{(4-x^2-2xh-h^2)-(4-x^2)}h=-\dfrac{2xh+h^2}h$

Then for $h\neq0$ , we can cancel common terms:

$\dfrac{f(x+h)-f(x)}h=-2x+h$

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3 years ago