Answer: 20
Step-by-step explanation:
Follow order of operations (PEMDAS)
20÷1÷[(10÷5)÷2] Given
20÷1÷[(2)÷2] Do 10÷5 in parenthesis
20÷1÷[(1)] Do (2)÷2
20÷1 Do 1÷[(1)]
20 Do 20÷1, and that is your answer
Ok so
Q.1=B
Q.2=B
Q.3(a)=(d-45)+m+65
(b)=d+m+20
Answer:
16 11/12
Step-by-step explanation:
7 2/3 + 3 1/4 =
7 8/12 + 3 3/12 =
10 11/12 + 6
16 11/12
Discussion
The discriminate is b^2 - 4*a*c
The general equation for a quadratic is ax^2 + bx + c
In this equation's case
a = 1
b= -5
c = - 3
Solve
(-5)^2 - 4*(1)*(-3)
25 - (-12)
25 + 12
37
Note
Since the discriminate is > 0, the roots are real and different. The roots do exist and there are 2 of them.
Let's write an inequality, such as follows: x < sqrt(50) < y. Square both sides of the equation. We get x^2 < 50 < y^2. Obviously, x is between 7 and 8. Also notice, that for integers a,b, (ab)^2/b^2, equals a^2. So let's try values, like 7.1. Using the previous fact, (7.1)^2, equals (71)^2/100. So, (7.1)^2, equals 50.41. Thus, our number is between 7 and 7.1. We find, with a bit of experimentation, that the square root of 50, is 7.07.