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2 years ago

6. What is the 14th partial sum for the arithmetic sequence where a1= 18 and d = 9.4?

Mathematics

2 answers:

RSB [31]2 years ago

4 0

Answer:

1107.4

Step-by-step explanation:

Took Test.

Marina86 [1]2 years ago

3 0

Answer:

Step-by-step explanation:

Its about drive its about power we stay hungry we devoure put in the work put in the power and take what's our

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f the principal is $350 and the interest rate is 3 percent, what is the simple interest earned in one year?

damaskus [11]

Answer:

$10.50

Step-by-step explanation:

The formula is Balance= Principle (starting amount) x Time x Interest rate. 350 x .03 x 1 is $10.50.

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3 years ago

Which Property is shown? (5•10) + (5•5) = 5( 10 + 5)

finlep [7]

Distributive Property

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3 years ago

Ben and Josh went to the roof of their 40-foot tall high school to throw their math books offthe edge.The initial velocity of Be

Taya2010 [7]

Answer

Josh's textbook reached the ground first

Josh's textbook reached the ground first by a difference of $t=0.6482$

Step-by-step explanation:

Before we proceed let us re write correctly the height equation which in correct form reads:

$h(t)=-16t^2 +v_{o}t+s$ Eqn(1).

Where:

$h(t)$ : is the height range as a function of time

$v_{o}$ : is the initial velocity

$s$ : is the initial heightin feet and is given as 40 feet, thus Eqn(1). becomes:

$h(t)=-16t^2 + v_{o}t + 40$ Eqn(2).

Now let us use the given information and set up our equations for Ben and Josh.

Ben:

We know that $v_{o}=60ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+60t+40$ Eqn.(3)

Josh:

We know that $v_{o}=48ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+48t+40$ Eqn. (4).

Now since we want to find whose textbook reaches the ground first and by how many seconds we need to solve each equation (i.e. Eqns. (3) and (4)) at $h(t)=0$ . Now since both are quadratic equations we will solve one showing the full method which can be repeated for the other one.

Thus we have for Ben, Eqn. (3) gives:

$h(t)=0-16t^2+60t+40=0$

Using the quadratic expression to find the roots of the quadratic we have:

$t_{1,2}=\frac{-b+/-\sqrt{b^2-4ac} }{2a} \\t_{1,2}=\frac{-60+/-\sqrt{60^2-4(-16)(40)} }{2(-16)} \\t_{1,2}=\frac{-60+/-\sqrt{6160} }{-32} \\t_{1,2}=\frac{15+/-\sqrt{385} }{8}\\\\t_{1}=4.3276 sec\\t_{2}=-0.5776 sec$

Since time can only be positive we reject the $t_{2}$ solution and we keep that Ben's book took $t=4.3276$ seconds to reach the ground.

Similarly solving for Josh we obtain

$t_{1}=3.6794sec\\t_{2}=-0.6794sec$

Thus again we reject the negative and keep the positive solution, so Josh's book took $t=3.6794$ seconds to reach the ground.

Then we can find the difference between Ben and Josh times as

$t_{Ben}-t_{Josh}= 4.3276 - 3.6794 = 0.6482$

So to answer the original question:

Whose textbook reaches the ground first and by how many seconds?

Josh's textbook reached the ground first
Josh's textbook reached the ground first by a difference of $t=0.6482$

3 0

3 years ago

please help! Create a function y=f(x) that has a removable discontinuity at x=2 and a non-removable discontinuity x=3. Fill in t

Alenkasestr [34]

Answer:

Step-by-step explanation:

7 0

3 years ago

UW= 2 and UX=y. Write an expression for WX

Eddi Din [679]

Divide each term by U and simplify. X=y/U and W=2/U. Next, solve the equation for y. Simplify the left side then cancel the common factor of U. 1/1*y/1=y

W=2/U. Multiply 1/1*y/1=y/1 so, y/1=y and W=2/U. Next, divide y/y to get 1 now y=y, still W=2/U. Now, move all terms containing y to the left side. Since, Y contains the variable to solve for, move it to the left side of the equation by subtracting y from both sides. Now, y-y=0 still W=2/U. Next, subtract y from y to get zero and still W=2/U. Subtract y from y to get zero or 0=0 and W=2/U is your expression since 0=0.

Next: UW=m and WX=y+14 write expression for UX

First, divide each term by W and simplify. U=m/W, WX=y+14. Next, solve the equation for Y. Move y from the right side of the equation to the left side. Still, U=m/W and y=-14+WX. We must reorder -14 and WX. U=m/w and y=WX-14.
Replace the variable U with m/W in the expression to (m/W)X. Next, simplify (m/W)X. Now, write X and a fraction with denominator 1. Looks like this
fractions are side by side m/W X/1 . Multiply, m/W and X/1 to get mX/W.
mX/W is your final expression for UW=m and WX=y+14 expression for UX.

8 0

3 years ago