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2 years ago

6. What is the 14th partial sum for the arithmetic sequence where a1= 18 and d = 9.4?

Mathematics

2 answers:

RSB [31]2 years ago

4 0

Answer:

1107.4

Step-by-step explanation:

Took Test.

Marina86 [1]2 years ago

3 0

Answer:

Step-by-step explanation:

Its about drive its about power we stay hungry we devoure put in the work put in the power and take what's our

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Complete parallel side 2

Gnoma [55]

Step-by-step explanation:

Assume length of side 2 = L

Area of parallelogram is Height x L

So, 72 = 8 x L

L = 9

8 0

3 years ago

How to figure it out

ollegr [7]

Y = kx
72 = k*3
73/3 = k
24 = k

y = 24x

4 0

3 years ago

Juliette is making a fruit salad.she purchased 9 2/3 ounces each of 6 different fruits . how many ounces of fruit did she purcha

Anettt [7]

9 2/3 total ounces is a total split up among 6 fruits.

So we need to divide 9 2/3 among the 6 fruits.

= 9 2/3 divide 6

= change 9 2 / 3 in improper fraction
= 9*3 + 2/3

= 29/3 divided by 6/1

= 29/3 x 1/6

= 29/18, change that to mixed fractions.

The answer is 1 11/18 ounces of each fruit.

3 0

3 years ago

I buy a MP3 player for £40 in a sale where it was 20% off. What was the original price

natta225 [31]

20% off means you paid only 80% of the original price.
0.8x=40
x=40÷0.8=50
so the original price is 50

6 0

3 years ago

Read 2 more answers

A University wanted to find out the percentage of students who felt comfortable reporting cheating by their fellow students. A s

Alla [95]

Answer:

The point estimate for this problem is 0.48.

Step-by-step explanation:

We are given that a University wanted to find out the percentage of students who felt comfortable reporting cheating by their fellow students.

A survey of 2,800 students was conducted and the students were asked if they felt comfortable reporting cheating by their fellow students. The results were 1,344 answered "Yes" and 1,456 answered "no".

Let $\hat p$ = proportion of students who felt comfortable reporting cheating by their fellow students

Now, point estimate ( $\hat p$ ) is calculated as;

$\hat p=\frac{X}{n}$

where, X = number of students who answered yes = 1,344

n = number of students surveyed = 2,800

So, Point estimate ( $\hat p$ ) = $\frac{1,344}{2,800}$

= 0.48 or 48%

5 0

3 years ago