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Rashid [163]
3 years ago
8

GEOMETRY HELP ASAP PLEASE

Mathematics
1 answer:
yarga [219]3 years ago
6 0
Haha I know this totally unhelpful but I do connections academy too. What quiz/test are you on
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Given below are descriptions of two lines.
Irina-Kira [14]

Answer:

y=x/3+5, y=x/3+3

Step-by-step explanation:

Line 1 : The gradient would be (7-3)/(6-(-6))=4/12=1/3, Therefore the answer is y=x/3+5

Line 2: The gradient would be (1-2)/((-6)-(-3))=(-1)/(-3)=1/3, Therefore the answer is y=x/3+3

6 0
3 years ago
What is the volume of this oblique cone? 432π cm³ ​324π​ cm³ ​288π​ cm³ ​144π​ cm³ Oblique cone with a radius of 10 centimeters
yawa3891 [41]

Volume of oblique cone is same as regular cone. The volume of the given oblique cone is  533.33 π​ cm³.

<h3>What is oblique cone?</h3>

Oblique cone is the cone the in which the vertex is not at the center of the base of cone.

The volume of the oblique cone is same as the volume of regular cone. The volume of oblique cone can be given as,

V=\dfrac{1}{3}\pi r^2h

Here, r is radius of the base of oblique cone and h is the height.

Given information-

The radius of the oblique cone is 10 cm.

The height of the oblique cone is 16 cm.

The image of oblique cone is attached below.

As the radius of the oblique cone is 10 cm and the height of the oblique cone is 16 cm.

Thus plug in the values in the formula of oblique cone as,

V=\dfrac{1}{3}\pi (10)^2\times16

Simplify it further as,

V=\dfrac{1}{3}\pi (100)\times16\\V=533.33\pi

Thus the volume of the given oblique cone is  533.33 π​ cm³.

Learn more about the oblique cone here;

brainly.com/question/2054073

6 0
2 years ago
The sophomore class at south high school raised $800 from the sale of tickets for the dance. tickets sold for $1.50 in advance,
Juli2301 [7.4K]

Answer:

44

Step-by-step explanation:

7 0
3 years ago
Solve this equation for x. Round your answer to the nearest hundredth. 0.77 = log x​
Alekssandra [29.7K]

Answer:

x ≈ 5.89

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Equality Properties

<u>Algebra II</u>

  • Exponential to Logarithmic:                                                                             \displaystyle b^m=x \rightarrow log_bx=m

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

0.77 = log(x)

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. [Equality Property] Raise both sides to the 10th power:                                \displaysytle 10^{0.77} = 10^{logx}
  2. Simplify:                                                                                                             \displaysytle x = 10^{0.77}
  3. Evaluate:                                                                                                           \displaysytle x = 5.88844
8 0
3 years ago
Lim x -&gt; infinity ((e^(3x)) - (e^(-3x)))/( (e^(3x)) + (e^(-3x)))
steposvetlana [31]
When x<span> approaches to </span><span>+∞</span><span> the function </span><span>e^<span>3x</span></span><span> becomes much bigger then </span><span>e^<span>−3x</span></span><span>, which obviously means that </span><span>e^<span>−3x</span></span><span> can be neglected in both numerator and denominator.
</span><span>
Here's how I figured this out: 

</span><span>lim <span>x →+∞ </span></span>= (<span><span><span>e^(<span>3x))</span></span>− (<span>e^(<span>−3x)) / (</span></span></span><span><span>e^<span>3x)) </span></span>+ (<span>e^(<span>−3x)) </span></span></span></span>= <span>lim <span>x → +∞ </span></span><span><span>e^<span>3x / </span></span><span>e^<span>3x </span></span></span>= 1
7 0
4 years ago
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