Question

A field with an area of 2880 ft^2 has the shape of a rectangle, whose length is 12 ft larger than its width. Find the dimensions of this field.

Answer 1

ANSWER

w=48,l=60

EXPLANATION

Let the width of the field be, w , then,

the length of the field will be:

$l = 12 + w$

The area of a rectangle is

$Area = lw$

This implies that:

$w(12 + w) = 2880$

Expand

${w}^{2} + 12w = 2880$

${w}^{2} + 12w - 2880 = 0$

$(x + 60)(x - 48) = 0$

This implies that,

$w = - 60 \: w = 48$

The dimensions are positive, the width is 48 and the length is 12+48=60