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3 years ago

The slope of the line below is 2. Which of the following is the point-slope form of the line? the x is 1 and the y is -1

Mathematics

2 answers:

sukhopar [10]3 years ago

5 0

The point slope form would be y+1=m(x-1)

anzhelika [568]3 years ago

3 0

Answer:

$(y+1)=2(x-1)$

Step-by-step explanation:

We have been given that the slope of a line is 2 and point (1,-1) in on our given line. We are asked to write the equation for our given line in point-slope form.

Since we know that point-slope form of an equation is: $(y-y_1)=m(x-x_1)$ , where

m = Slope of line,

$(x_1,y_1)$ = Coordinates of the given point on line.

Upon substituting our given values in point-slope form of equation we will get,

$(y--1)=2(x-1)$

$(y+1)=2(x-1)$

Therefore, the equation $(y+1)=2(x-1)$ represents our given line in point-slope form.

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What is 14 subtracted from a number

eduard

Answer:

x-14

Step-by-step explanation:

We don't know what this number is so we label it as x or substitute it with x:

14 subtracted from it means, the number minus 14

Therefore our answer is :

x-14

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2 years ago

Read 2 more answers

The function f(x)=(x-5)^2 +2 is not one-to-one. Identify a restricted domain that makes the function one-to-one, and find the in

Anon25 [30]

We have been given a quadratic function $f(x)=(x-5)^{2} +2$ and we need to restrict the domain such that it becomes a one to one function.

We know that vertex of this quadratic function occurs at (5,2).

Further, we know that range of this function is $[2,\infty)$ .

If we restrict the domain of this function to either $(-\infty,5]$ or $[5,\infty)$ , it will become one to one function.

Let us know find its inverse.

$y=(x-5)^{2}+2$

Upon interchanging x and y, we get:

$x=(y-5)^{2}+2$

Let us now solve this function for y.

$(y-5)^{2}=x-2\\
y-5=\pm \sqrt{x-2}\\
y=5\pm \sqrt{x-2}\\$

Hence, the inverse function would be $f^{-1}(x)=5+\sqrt{x-2}$ if we restrict the domain of original function to $[5,\infty)$ and the inverse function would be $f^{-1}(x)=5-\sqrt{x-2}$ if we restrict the domain to $(-\infty,5]$ .