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Otrada [13]
3 years ago
9

Solve 2t+3y=x-5 solve for t

Mathematics
1 answer:
mote1985 [20]3 years ago
7 0

Answer:f

Step-by-step explanation:

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makvit [3.9K]
3/4*3/3=9/12

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F(x) = Square root of x plus eight.; g(x) = 8x - 12 Find f(g(x))
Liono4ka [1.6K]
f(x)= \sqrt{x+8} \Rightarrow f(g(x))= \sqrt{(8x-12)+8} = \sqrt{8x -4}
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Phillip and his two friends need to raise at least 2,400 for their study abroad trip to europe. so far they have raised 600$. Wr
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x+600≥2400

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How many 2-letter combinations can be created from the distinct letters in the word “mathematician”? Assume that the order of th
kupik [55]
Hello!

this problem comes with a slightly complex math equation that I had to ask my math teacher about, so I hope it helps.

<span>The expression n! means "the product of the integers from 1 to n"
</span>this can be said for any variable

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Find the equation of the line through the point (–2, –2) that is perpendicular to the line y = 2x – 1.
lawyer [7]

Hi student, let me help you out!

.....................................................................................................

---------------------------------------------

<h3>Part 1.</h3>

Perpendicular lines have slopes that are <u>opposite inverses </u>of each other.

The opposite inverse of 2 is \mathrm{-\cfrac{1}{2}}.

Now let's stick in this number into the equation \mathrm{y=mx+b}:

\mathrm{y=-\cfrac{1}{2}x+b}.  Let's carry out several operations to determine the y intercept.

First, let's stick in -2 for x and y (Do you remember that the line passes through (-2,-2)? We're given that piece of information.)

\mathrm{-2=-\cfrac{1}{2}\times(-2)+b}.

You are probably thinking, "Why did you do that and just complicate things?" Wait for it! ^-^

Upon simplifying this, we obtain: \mathrm{-2=1+b}. See, it's nice and smooth now.

One last operation remains. We need to subtract 1 from both sides: \mathrm{-3=b}.

∴, the equation of the line is: \mathrm{\underline{\boxed{y=-\cfrac{1}{2}-3}}}

Hope this helped you out, ask in comments if any queries arise.

Best Regards!

\star\bigstar\underline{\underline{\overline{\overline{\bold{Reach\:Far.\:Aim\:high.\:Dream\:big.}}}}}\bigstar\star

\underline{\rule{300}{3}}

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