Answer:
Step-by-step explanation:
First confirm that x = 1 is one of the zeros.
f(1) = 2(1)^3 - 14(1)^2 + 38(1) - 26
f(1) = 2 - 14 + 38 - 26
f(1) = -12 + 38 = + 26
f(1) = 26 - 26
f(1) = 0
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next perform a long division
x -1 || 2x^3 - 14x^2 + 38x - 26 || 2x^2 - 12x + 26
2x^3 - 2x^2
===========
-12x^2 + 28x
-12x^2 +12x
==========
26x -26
26x - 26
========
0
Now you can factor 2x^2 - 12x + 26
2(x^2 - 6x + 13)
The discriminate of the quadratic is negative. (36 - 4*1*13) = - 16
So you are going to get a complex result.
x = -(-6) +/- sqrt(-16)
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2
x = 3 +/- 2i
f(x) = 2*(x - 1)*(x - 3 + 2i)*(x - 3 - 2i)
The zeros are
1
3 +/- 2i
You can use trigonometry and the tangent to get:
tan(11°)=150/x
so x=772 ft
Answer:
C. F(x) = 4x² + 1
Step-by-step explanation:
→The function F(x) shifted 1 unit upwards, meaning there needs to be a 1 being added to the function.
→In addition, the function F(x) has grown narrower, compared to the function G(x). This is from the absolute value of a number being greater than 1, which is being multiplied.
<u>This means the correct answer should be "C. F(x) = 4x² + 1."</u>
Answer:
Letter A
Need more help you can ask me
If angle ec is a bisector then angles Bec and ced are the same making them both 4x+1. we know a line segment equals 180°. so if we take the 11x-12 and add it to 2(4x+1) we end up with 19x-10=180. you add 10 to both sides and get 19x=190 then you divide by both sides. you'll end up with x=10. you plug In the 10 with aeb and aec and add them together to get 139°. if you're looking for the equation, it's 15x-11.
