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BartSMP [9]
3 years ago
12

(2k + 3)(k - 1) A. 2k^2 + k – 3 B. 2k^2 + k + 2 C. 2k^2 – k – 3 D. 2k^2 – k + 2

Mathematics
1 answer:
boyakko [2]3 years ago
6 0

(2k+3)(k-1)

Use the distribute property

(2k)(k)+(2k)(-1)+(3)(k)+(3)(-1)

= 12k²-2k+3k-3

= 2k²+k-3


The answer is A


Good night

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In △XYZ, m∠Z = 34, x = 61 cm, and z = 42 cm. Find m∠X. Round your answer to the nearest tenth of a degree.
Elza [17]
M∠X = 54.3°.

Using the Law of Sines, we have:
\frac{\sin{Z}}{z}=\frac{\sin{X}}{x}
\\
\\\frac{\sin{34}}{42}=\frac{\sin{X}}{61}

Cross multiplying gives us
61(sin 34) = 42(sin X)

Divide both sides by 42:
(61(sin 34))/42 = (42(sin X))/42
(61(sin 34))/42 = sin X

Take the inverse sine of both sides:
sin⁻¹((61(sin 34))/42) = sin⁻¹(sin X)
54.3 = X
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Mindy buys a $36 sweater on a 15% off sale. How much will she pay if the sales tax is 6%?
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32.44 is the final amount for the sweater
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Melinda earns 5 minutes to play video games for every hour she spends on homework.
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She gets 15 minutes to play video games.

Step by step:

For every 1 hour = 5 minutes, so 1x3 = 3 hours, 5x3 = 15 minutes.

5 0
3 years ago
A researcher wants to show the mean from population 1 is less than the mean from population 2 in​ matched-pairs data. if the obs
Veronika [31]

Answer:

The null hypothesis is represented as

H₀: μd = 0

The alternative hypothesis is represented as

H₁: μd < 0, that is, mud less than 0.

Step-by-step explanation:

Correct Question

A researcher wants to show the mean from population 1 is less than the mean from population 2 in​ matched-pairs data. if the observations from sample 1 are xi and the observations from sample 2 are yi​, and di = (xi -yi​), then the null hypothesis is h0​: μd = 0 and the alternative hypothesis is h1​: μd ​___ 0.

Solution

For hypothesis testing, the first thing to define is the null and alternative hypothesis.

In hypothesis testing, especially one comparing two sets of data, the null hypothesis plays the devil's advocate and usually takes the form of the opposite of the theory to be tested. It usually contains the signs =, ≤ and ≥ depending on the directions of the test. It usually maintains that, with random chance responsible for the outcome or results of any experimental study/hypothesis testing, its statement is true.

The alternative hypothesis usually confirms the theory being tested by the experimental setup. It usually contains the signs ≠, < and > depending on the directions of the test. It usually maintains that significant factors other than random chance, affect the outcome or results of the experimental study/hypothesis testing and result in its own statement.

For this question, we are aiming to show that the mean from population 1 (μₓ) is less than the mean from population 2 (μᵧ).

The null hypothesis would be that there isn't significant evidence to suggest that the mean from population 1 (μₓ) is less than the mean from population 2 (μᵧ). That is, the mean from population 1 (μₓ) is not less than the mean from population 2 (μᵧ).

The alternative hypothesis is that there is significant evidence to suggest that mean from population 1 (μₓ) is less than the mean from population 2 (μᵧ).

Mathematically, if μₓ and μᵧ are the means of population 1 and 2 respectively and μd is the mean of the differences between population 1 and population 2, μd = μₓ - μᵧ

The null hypothesis is represented as

H₀: μₓ = μᵧ or μd = 0

The alternative hypothesis is represented as

H₁: μₓ < μᵧ or μd < 0

Hope this Helps!!!

8 0
3 years ago
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