Find the number of moles
C = n / V
C(Concentration) = 0.30 moles / L
V ( Volume) = 2 L
n = ??
n = C * V
n = 0.30 mol / L * 2 L
n = 0.60 mol
Find the molar mass
2Na = 23 * 2 = 46 grams
1S = 32 * 1 = 32 grams
O4 = 16 * 4 = 64 grams
Total = 142 grams / mol
Find the mass
n = given mass / molar mass
n = 0.06 mol
molar Mass = 142 grams / mol
given mass = ???
given mass = molar mass * mols
given mass = 142 * 0.6
given mass = 85.2 grams.
85.2 are in a 2 L solution that has a concentration of 0.6 mol/L
CaCl2 and KCl are both salts which dissociate in water
when dissolved. Assuming that the dissolution of the two salts are 100 percent,
the half reactions are:
<span>CaCl2 ---> Ca2+ + 2 Cl-</span>
KCl ---> K+ + Cl-
Therefore the total Cl- ion concentration would be coming
from both salts. First, we calculate the Cl- from each salt by using stoichiometric
ratio:
Cl- from CaCl2 = (0.2 moles CaCl2/ L) (0.25 L) (2 moles
Cl / 1 mole CaCl2)
Cl- from CaCl2 = 0.1 moles
Cl- from KCl = (0.4 moles KCl/ L) (0.25 L) (1 mole Cl / 1
mole KCl)
Cl- from KCl = 0.1 moles
Therefore the final concentration of Cl- in the solution
mixture is:
Cl- = (0.1 moles + 0.1 moles) / (0.25 L + 0.25 L)
Cl- = 0.2 moles / 0.5 moles
<span>Cl- = 0.4 moles (ANSWER)</span>
Answer:
speed
Explanation:
if it is starting to move faster, the speed increases
Explanation:
The balanced reaction equation is as follows.

As it is given that 2.3 times the amount of
is needed to drive this reaction we can calculate just how much
we have, keeping in mind we only need 5 moles of
.
Hence,
= 11.5 moles of
= 12 (moles approx)
Therefore, it means that
is our limiting reagent, so product formed will be as follows.
:
= 1:4 meaning we create 4 moles of
:
= 1:3 meaning we create 3 moles of 
As, in the given reaction we had 12 moles of
, but 5 moles were consumed in the reaction meaning we have:
12 - 5 = 7 moles of
Thus, we will add up all the moles and get the ratios for each gas as follows.
7 + 4 + 3 = 14 moles
= 0.285
= 0.214
Hence,
will be consumed completely.