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Olenka [21]
3 years ago
12

What is the noble-gas electron configuration for bromine?

Chemistry
1 answer:
marshall27 [118]3 years ago
5 0
My Answer: (Ar) 3d10 4s2 4p5

Hope I helped! :D
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How do I do question number 2?
ale4655 [162]

Answer:

I cant help

Explanation:

4 0
3 years ago
What does the process of natural selection involve
Lorico [155]

Answer:

Only the organisms best adapted to their environment tend to survive and transmit their genetic characters in increasing numbers to succeeding generations while those less adapted tend to be eliminated.

Explanation:

According to Darwin's Theory of Evolution.

Hope this helped.

5 0
3 years ago
An atom is a small building block that forms matter. Many different models of an atom have been made over the years. Which of th
puteri [66]

Answer:

<em>The correct option is A) The atom has changed over the years.</em>

Explanation:

Option A is not correct because an atom does not change. It remains the same always. The structure of an atom will always contain neutrons, protons and electrons.

Scientific theories tend to change over time as new information is brought up. Novel techniques lead to more advanced experiments and results. As a result, a scientific theory is subjected to change whenever evidence is found for a new theory which challenges the older one.

The atomic theory has changed many times due to novel scientific techniques and experiments.

8 0
3 years ago
Balance the following chemical equation.<br><br> CCl4 -&gt; ___ C+ ___ Cl2
Bingel [31]

Answer:

Explanation:

CCl4 => C + 2Cl2

6 0
3 years ago
For the Zn - Cu^2+ voltaic cell Zn(s) + Cu^2+(aq, 1M) + Cu(s) E degree _cell = 1.10 V Given that the standard reduction potentia
Fittoniya [83]

Answer : The value of E^o_{(Cu^{2+}/Cu)} is, 0.34 V

Explanation :

Here, copper will undergo reduction reaction will get reduced. Zinc will undergo oxidation reaction and will get oxidized.

The oxidation-reduction half cell reaction will be,

Oxidation half reaction:  Zn\rightarrow Zn^{2+}+2e^-

Reduction half reaction:  Cu^{2+}+2e^-\rightarrow Cu

Oxidation reaction occurs at anode and reduction reaction occurs at cathode. That means, gold shows reduction and occurs at cathode and chromium shows oxidation and occurs at anode.

The overall balanced equation of the cell is,

Zn+Cu^{2+}\rightarrow Zn^{2+}+Cu

To calculate the E^o_{(Cu^{2+}/Cu)} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

E^o_{cell}=E^o_{(Cu^{2+}/Cu)}-E^o_{(Zn^{2+}/Zn)}

Putting values in above equation, we get:

1.10V=E^o_{(Cu^{2+}/Cu)}-(-0.76V)

E^o_{(Cu^{2+}/Cu)}=0.34V

Hence, the value of E^o_{(Cu^{2+}/Cu)} is, 0.34 V

8 0
3 years ago
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