Answer:
N2 + H2 --> 2 NH
Explanation:
You need to add 2 to make it correct
pH is referred to as the scale to describe the hydronium ion concentration of a
solution. It is used to measure the acidity or basicity of a solution. pH of an acidic solution is less than 7, a neutral solution is 7, and a basic solution is greater than 7.
pH can be calculated using the formula:
![pH = - log [H_{3}O^{+}]](https://tex.z-dn.net/?f=%20pH%20%3D%20-%20log%20%5BH_%7B3%7DO%5E%7B%2B%7D%5D%20%20%20)
Given the pH of solution is 3.2.
Finding out the concentration of hydronium ion from pH.
![pH = - log[H_{3}O^{+}]](https://tex.z-dn.net/?f=%20pH%20%3D%20-%20log%5BH_%7B3%7DO%5E%7B%2B%7D%5D)
![3.2 = - log [H_{3}O^{+}]](https://tex.z-dn.net/?f=%203.2%20%3D%20-%20log%20%5BH_%7B3%7DO%5E%7B%2B%7D%5D%20%20%20)
![[H_{3}O^{+}] = 10^{-3.2}](https://tex.z-dn.net/?f=%20%5BH_%7B3%7DO%5E%7B%2B%7D%5D%20%3D%2010%5E%7B-3.2%7D%20%20%20%20)
![[H_{3}O^{+}] = 6.3 * 10^{-4} M](https://tex.z-dn.net/?f=%20%5BH_%7B3%7DO%5E%7B%2B%7D%5D%20%3D%20%20%206.3%20%2A%2010%5E%7B-4%7D%20M%20%20)
Therefore, the hydronium ion concetration of the solution is 
Supersaturated is the correct answer
Answer:
Net ionic equation:
Ba²⁺(aq) + SO₄²⁻(aq) → BaSO₄(s)
Explanation:
Chemical equation:
BaCl₂ + Na₂SO₄ → BaSO₄ + NaCl
Balanced Chemical equation:
BaCl₂(aq) + Na₂SO₄(aq) → BaSO₄(s) + 2NaCl(aq)
Ionic equation:
Ba²⁺(aq) + 2Cl⁻(aq) + 2Na⁺(aq) + SO₄²⁻(aq) → BaSO₄(s)+ 2Na⁺(aq) + 2Cl⁻ (aq)
Net ionic equation:
Ba²⁺(aq) + SO₄²⁻(aq) → BaSO₄(s)
The Cl⁻(aq) and Na⁺ (aq) are spectator ions that's why these are not written in net ionic equation. The BaSO₄ can not be splitted into ions because it is present in solid form.
Spectator ions:
These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.
