Decomposition reaction D. 2H20⇒ 2H2 + O2
<h3>Further explanation
</h3>
Every chemical reaction involves a compound consisting of reactants and products
Reactants are compounds that react and form new compounds called products
There are several forms of reactions that can occur, including single replacement, double replacement, synthesis, decomposition, etc.
A. 2C2H6 + 702 ⇒ 4CO2 + 6H20
Combustion : reaction of Hydrocarbon and Oxygen
B. AgNO3 + LiCl → AgCl + LINO3
Double replacement : there is an ion exchange between two ion compounds in the reactant to form two new ion compounds in the product
C. Ca + MgS → CaS + Mg
Single replacement :one element replaces the other elements of a compound to produce new elements and compounds
D. 2H20⇒ 2H2 + O2
Decomposition : One compound breaks down into 2 components
Cobalt sulphate is the usual source of water-soluble cobalt since it is the most economical salt and shows less tendency to deliquesce or dehydrate
<u>Answer:</u> The balanced chemical equation for the decomposition of nitroglycerin is written below.
<u>Explanation:</u>
Decomposition reaction is defined as the reaction in which a single large substance breaks down into two or more smaller substances.
Every balanced chemical equation follows law of conservation of mass.
A balanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side is equal to the total number of individual atoms on product side.
The balanced chemical equation for the decomposition of nitroglycerin follows:
By Stoichiometry of the reaction:
1 mole of liquid nitroglycerin decomposes into 12 moles of carbon dioxide gas, 10 moles of gaseous water, 6 moles of dinitrogen gas and 1 mole of dioxygen gas.
Hence, the balanced chemical equation for the decomposition of nitroglycerin is written above.
Beryllium Oxide has a molecular formula Be-O
% covalent character in Be-O = 100 - % ionic character in Be-O
Now,
% ionic character = {1 - exp[(-0.25)(E(Be)-E(O))²]}*100
where,
E(Be) and E(O) are the electronegativity values of Be and O
Based on the Paulings scale:-
E(Be) = 1.57
E(O) = 3.44
% ionic = {1 - exp[(-0.25)(1.57-3.44)²]}*100 = 58.28%
Therefore, % covalent = 100 -58.28 = 41.72%
Ans: b) 41 percent
Answer:
no
Explanation:
if you are referring to the first question, the answer is no. the equation is unbalanced because the left side has 4 hydrogens and the right has only 2, and the left has 2 oxygens while the right has 3. this means it does not follow the law of conservation of mass because each side has a different mass.
