Answer:
The domain can't be found by this equation u have to look at the question one more time because it should say what it is.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Then Joe and Jeremy will do the job in one hour time
Joe takes 5 hours to do the job then in one hour time he does 1/5
Joe takes 400% as long as the time it takes Jeremy to finish the job
then 5 hours 400
x ?? 100 x = 5/4
So Jeremy will take 5/4 hours to do the job.
Then in one hour working together Joe and Jeremy they will do
1/5 + 1/ (5/4) = 1/5 + 4/5 = 5/5 = 1
Then Joe and Jeremy will do the job in one hour time
And Joe and Joanne will do half job in one hour
Hello,
Let's x then number of students.
x is divisible by 12,15,18 thus by 180 (lcm)
x=180*k is a square
2²*3²*5*k= a square ==> k=5
x=180*5=900
Proof:
900/12=75
900/15=60
900/18=50
900=30²
Answer:
sin(2x)=cos(π2−2x)
So:
cos(π2−2x)=cos(3x)
Now we know that cos(x)=cos(±x) because cosine is an even function. So we see that
(π2−2x)=±3x
i)
π2=5x
x=π10
ii)
π2=−x
x=−π2
Similarly, sin(2x)=sin(2x−2π)=cos(π2−2x−2π)
So we see that
(π2−2x−2π)=±3x
iii)
π2−2π=5x
x=−310π
iv)
π2−2π=−x
x=2π−π2=32π
Finally, we note that the solutions must repeat every 2π because the original functions each repeat every 2π. (The sine function has period π so it has completed exactly two periods over an interval of length 2π. The cosine has period 23π so it has completed exactly three periods over an interval of length 2π. Hence, both functions repeat every 2π2π2π so every solution will repeat every 2π.)
So we get ∀n∈N
i) x=π10+2πn
ii) x=−π2+2πn
iii) x=−310π+2πn
(Note that solution (iv) is redundant since 32π+2πn=−π2+2π(n+1).)
So we conclude that there are really three solutions and then the periodic extensions of those three solutions.
5.8K views
View upvotes
5
Related Questions (More Answers Below)
In 6 weeks.
For this problem, you need to determine
the least common multiple of the numbers given which is 2, 3, and 6. You
can calculate the LCM of multiple numbers by pairs.
The LCM of 2 and 3 is 6 because 6 is the smallest possible number that can be evenly divided by both 2 and 3.
Now you need the LCM of 6 and 6. Which is also 6, because 6 is the smallest number that can be evenly divided by 6.
So the LCM of 2, 3, and 6 is 6. So in 6 weeks, Clea will once again
have a music less, attend dance class, and have a dental appointment,
all during the same week.
