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matrenka [14]
3 years ago
15

PLEASE ANSWER ASAP!!!!!! I WILL LOVE FOREVER LOL!!!

Mathematics
2 answers:
const2013 [10]3 years ago
5 0

Point-slope form:  y - y₁ = m(x - x₁)

(m is the slope, (x₁, y₁) is the point you are given that is on the line)

You know:

m = 5

(x₁, y₁) = (-2, -3)         So substitute/plug it into the equation

y - y₁ = m(x - x₁)

y - (-3) = 5(x - (-2))   (two negative signs cancel each other out and become positive)

y + 3 = 5(x + 2)    Your answer is A

Lunna [17]3 years ago
4 0

Answer:

A. y + 3 = 5(x+2)

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Find the domain of f(x).<br> -<br> 3x + 4/9x + 45?
sweet [91]

Answer:

The domain can't be found by this equation u have to look at the question one more time because it should say what it is.

Step-by-step explanation:

8 0
3 years ago
Working together, Joe and Joanne finish a job in 2 hours. How long will it take Jeremy and Joe to finish the job? (1) Working al
zloy xaker [14]

Answer:

Step-by-step explanation:

Then Joe and Jeremy will do the job in one hour time

Joe takes 5 hours to do the job  then in one hour time he does  1/5

Joe takes 400% as long as the time it takes Jeremy to finish the job

then       5 hours     400

                x  ??         100         x = 5/4  

So Jeremy will take 5/4 hours to do the job.

Then in one hour working together Joe and Jeremy they will do

1/5 + 1/ (5/4)     =    1/5  +  4/5   =  5/5   =  1

Then Joe and Jeremy will do the job in one hour time

And Joe and Joanne will do half job in one hour

7 0
3 years ago
The students in a school can be arranged in 12, 15 and 18 equal rows and also into a solid square. What is the lowest number of
ASHA 777 [7]

Hello,

Let's x then number of students.

x is divisible by 12,15,18 thus by 180 (lcm)

x=180*k is a square

2²*3²*5*k= a square ==> k=5

x=180*5=900

Proof:

900/12=75

900/15=60

900/18=50

900=30²

4 0
3 years ago
PLZ HELP!!! I Will give brainliest. What is the value of x in sin(3x)=cos(6x) if x is in the interval of 0≤x≤π/2
sertanlavr [38]

Answer:

sin(2x)=cos(π2−2x)

So:

cos(π2−2x)=cos(3x)

Now we know that cos(x)=cos(±x) because cosine is an even function. So we see that

(π2−2x)=±3x

i)

π2=5x

x=π10

ii)

π2=−x

x=−π2

Similarly, sin(2x)=sin(2x−2π)=cos(π2−2x−2π)

So we see that

(π2−2x−2π)=±3x

iii)

π2−2π=5x

x=−310π

iv)

π2−2π=−x

x=2π−π2=32π

Finally, we note that the solutions must repeat every 2π because the original functions each repeat every 2π. (The sine function has period π so it has completed exactly two periods over an interval of length 2π. The cosine has period 23π so it has completed exactly three periods over an interval of length 2π. Hence, both functions repeat every 2π2π2π so every solution will repeat every 2π.)

So we get ∀n∈N

i) x=π10+2πn

ii) x=−π2+2πn

iii) x=−310π+2πn

(Note that solution (iv) is redundant since 32π+2πn=−π2+2π(n+1).)

So we conclude that there are really three solutions and then the periodic extensions of those three solutions.

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Related Questions (More Answers Below)

5 0
3 years ago
Clea attends music lessons every 2 weeks, dance class every 3 weeks, and has a dental appointment every 6 weeks. If she attends
Basile [38]
In 6 weeks.



For this problem, you need to determine the least common multiple of the numbers given which is 2, 3, and 6. You can calculate the LCM of multiple numbers by pairs.



The LCM of 2 and 3 is 6 because 6 is the smallest possible number that can be evenly divided by both 2 and 3.



Now you need the LCM of 6 and 6. Which is also 6, because 6 is the smallest number that can be evenly divided by 6.



So the LCM of 2, 3, and 6 is 6. So in 6 weeks, Clea will once again have a music less, attend dance class, and have a dental appointment, all during the same week.
7 0
4 years ago
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