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3 years ago

Please assist me in 6-30

Mathematics

1 answer:

Ymorist [56]3 years ago

8 0

Answer:

Yes to both.

Step-by-step explanation:

It is true that

$\dfrac{x}{y}=1 \iff x=y$

In fact, if you know that x/y=1, just multiply both sides by y to get x=y. On the other hand, if you know that x=y (and they are not zero), you can divide both sides by y to get x/y=1.

Since the two expressions are equivalent, you can always use Phil's or Don's expression, at will.

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PLEASE HELP! I HAVE TWO QUESTIONS AND WILL GIVE 100PTS AND BRAINLIEST IF CORRECT!

Volgvan

Answer:

1) $283.50

2) 65.21 meters.

Step-by-step explanation:

Part 1)

We know that a spool of ribbon holds 6.75 meters.

A craft club buys 21 spools.

So, the total length of ribbon bought is:

$T=21(6.75)=141.75\text{ meters}$

Each meter costs $2. So, the total cost will be:

$141.75(2)=\$ 283.50$

Part 2)

A spool holds 6.75 meters.

We bought 21 of them, so that total length we have is 141.75 meters.

The club used 76.54 meters.

So, the amount of ribbon that is left is represented by:

$141.75-76.54$

Subtract:

$=65.21\text{ meters}$

So, 65.21 meters of ribbon will be left.

7 0

3 years ago

Read 2 more answers

Find f(x) and g(x) so the function can be expressed as y = f(g(x)). y = Two divided by x squared. + 3

kodGreya [7K]

Hello,

g(x)=x²+3
f(x)=2/x
so f(g(x))=f(x²+3)=2/(x²+3)

Explainations:

f(y)=2/y
f(4y)=2/(4y)
f(x²)=2/x²
f(x²+3)=2/(x²+3)

4 0

3 years ago

(Brainliest to the person that get its right)

oksian1 [2.3K]

<h3>Answer: Choice B</h3>

c^2-2cd+d^2 = (c-d)^2

We can verify this with the following steps

(c-d)^2 = (c-d)(c-d)

(c-d)^2 = c(c-d) - d(c-d)

(c-d)^2 = c^2-cd-cd+d^2

(c-d)^2 = c^2-2cd+d^2

6 0

2 years ago

Simplify this expression.

Grace [21]

11x2 would be your answer.

6 0

3 years ago

Read 2 more answers

Convert 12.045 to base 10

jeyben [28]

Answer:

12.045 is already in base 10, since it can'be binary or hexadecimal,

it's a denary(decimal) number, and decimal numbers are base 10

5 0

3 years ago

Please assist me in 6-30​

Please assist me in 6-30