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anyanavicka [17]
4 years ago
6

What is the length of XQY?

Mathematics
2 answers:
yulyashka [42]4 years ago
3 0

Answer:

88

Step-by-step explanation:

First you must find the circumference of the entire circle and to do this you use 2πr. The radius in this case is PX=15. This means that the circumference is 30π. Now to find the arc length, we know that the measure of arc XY is 23 degrees, and since there are 360 total degrees in a circle, we must subtract 23 from 360 to get 337° as the measure of arc XQY. Now we have to find what portion of the circumference of the circle is in this arc, and to do this you divide the arc length (337°) by 360° and multiply by the circumference of the circle. Doing this would get you \frac{337}{360} *30\pi which equals ~28. Finally, you have to multiply this by the value of pi and get approximately 88, which is your answer.

kompoz [17]4 years ago
3 0
The answer is 88 for the question
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HELPPPP JUST 2 QUESTIONS BASED ON PYTHAGOREAN THEOREM AND IM CONFUSED HELPPPP​
Anna007 [38]

9514 1404 393

Answer:

  3. no; does not have the correct ratio to other sides

  4. (1; right), (2; obtuse), (3; right)

Step-by-step explanation:

3. There are a couple of ways you can go at this.

a) the ratio of sides of a 30°-60°-90° right triangle (half an equilateral triangle) is 1 : √3 : 2. Here, the ratio of sides is ...

  (√30/2) : √15 : √30 = 1 : √2 : 2 . . . . MQ is <em>not</em> the height

b) the height is perpendicular to the base, so if MQ were the height, the sides of the triangle would satisfy the Pythagorean theorem:

  LQ² +MQ² = LM²

  (√30/2)² +(√15)² = (√30)²

  30/4 +15 = 30

  22.5 = 30 . . . . NOT TRUE

The length MQ cannot be the height of ∆LMN. (It is too short.)

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4. To see if these lengths form a right triangle, you can test them in the Pythagorean theorem relation. In the attached we have reformulated the equation so it gives a value of 0 if the triangle is a right triangle:

  c² = a² +b² . . . . . Pythagorean theorem

  c² -a² -b² = 0 . . . . rewritten

If the value of c² -a² -b² is not zero, then the side lengths do not form a right triangle. The attached shows this math performed by a graphing calculator. The results are ...

  1. right triangle
  2. not a right triangle — long side is too long, so the triangle is obtuse
  3. right triangle

_____

<em>Additional comment</em>

The attached table demonstrates an artifact of computer arithmetic. Not all numbers can be represented exactly in a computer, so a difference that is expected to be zero using exact arithmetic may be slightly different from zero when computed by a computer or calculator. Here, we see a difference of about 6×10^-14 when zero is expected. On most calculators (with 10, or 12 displayed digits), this would be displayed as 0.

The same calculation done "by hand" gives ...

  (√425)² -5² -20² = 425 -25 -400 = 0 . . . Triangle 1 is a <em>right triangle</em>

4 0
3 years ago
What kind of triangle is abc. Select all that apply. Geometry
pshichka [43]

Answer:

Right, Isosceles

Step-by-step explanation:

The side lengths of this triangle : 2√8 2√5 2√5

Scalane triangle has all side lengths in different measure but in this triangle we have two side lengths equal

Right triangle has a right angle with 90° and the square measure of hypotenuse is equal to sum of the square length of two side lengths in this triangle since 2√5 + 2√5 = 2√8 we can say that this is a right triangle.

Isosceles triangle are triangles with two side lengths equal to each other

Equilateral triangles are triangles with all side lengths equal to each other but we know one of the side length in this triangle is different

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6 0
3 years ago
Find the area of the regular polygon. Round to the nearest tenth.
mojhsa [17]

Given:

Side length = 12 in

To find:

The area of the regular polygon.

Solution:

Number of sides (n) = 6

Let us find the apothem using formula:

$a=\frac{s}{2 \tan \left(\frac{180^\circ}{n}\right)}

where s is side length and n is number of sides.

$a=\frac{12}{2 \tan \left(\frac{180^\circ}{6}\right)}

$a=\frac{6}{ \tan (30^\circ)}

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$a=6\sqrt{3}

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$A=\frac{1}{2}(72)(6\sqrt{3} )

A=216 \sqrt{3}

A=374.1 in²

The area of the regular polygon is 374.1 in².

4 0
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Suppose you carry out a significance test of h0: μ = 8 versus ha: μ &gt; 8 based on sample size n = 25 and obtain t = 2. 15. Fin
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Using a t-distribution calculator and finding the p-value, the correct option regarding the conclusion is given by:

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It also involves the significance level, as follows.

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It is less than 0.05, hence option a is correct.

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5 0
3 years ago
Whats the square root of 9
kolezko [41]
There are two solutions to this question, one is positive and the other is negative:
\sqrt{9} =3\ or\ -3
7 0
3 years ago
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