Hello,
f(x)=2x^3-x^2-4x+9=(((0+2)x-1)x-4)x+9
f(3)=(((0+2)*3-1)*3-4)*3+9=((2*3-1)*3-4)-3+9=(5*3-4)*3+9=11*3+9=33+9=42
or
f(3)=2*3^3-3^2-4*3+9=2*27-9-12+9=54-12=42
Answer:
I think that a Cube Root Function
Step-by-step explanation:
A. expanded, you get XxXxXxXxXxXxXxX over XxXxXxXxX
b.XxXxX or X³
c. I would just cancel out the 5 Xs on the top line against the 5 Xs on the bottom, leaving X³.