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MrMuchimi
3 years ago
10

if the lengths of two sides of a triangle are 24 and 18, what is the largest possible integer length of the third side of the tr

iangle?
Mathematics
2 answers:
ch4aika [34]3 years ago
6 0

Answer:

41

Step-by-step explanation:

galben [10]3 years ago
3 0

Answer:

41\ units

Step-by-step explanation:

As\ we\ know\ that,\\The\ sum\ of\ two\ sides\ of\ a\ triangle\ will\ always\ be\ greater\ than\ the\ Third\ Side.\\Hence,\\As\ we\ are\ given,\\Length\ of\ Side\ 1=24\ units\\Length\ of\ Side\ 2=18\ units\\Hence,\\The\ Length\ of\ Side\ 3

The\ nearest\ integer\ lesser\ than\ 42\ is\ 42-1\ or\ 41.\\Hence,\\The\ largest\ possible\ integer\ length\ of\ the\ third\ side\ of\ the\ triangle=41\ units

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Answer:

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Step-by-step explanation:

Open box has been made from a metal sheet measuring 3 ft and 8 ft.

Let four square pieces were removed from the four corners with one side measurement x ft.

Volume of the open box = Length × width × height

Length of the box = (3 - 2x) ft

Width of the box = (8 - 2x) ft

Height of the box = x ft

Volume of the box = (3 - 2x)(8 - 2x)x

V = (24 - 6x - 16x + 4x²)x

V = 24x - 22x² + 4x³

Now we take the derivative of V with respect to x and equate the derivative to zero,

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V' = 0

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3x² - 11x + 6 = 0

3x² - 9x - 2x + 6 = 0

3x(x - 3) - 2(x - 3) = 0

(3x - 2)(x - 3) = 0

(3x - 2) = 0

and (x - 3) = 0

Therefore, x = 3, \frac{2}{3}

For x = 0.67

Length of the box = (3 - 2x) = 3 - 1.34

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Volume of the box = 0.67 × 1.66 × 6.66

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Step-by-step explanation:

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