Find the inertia tensor for an equilateral triangle in the xy plane. Take the mass of the triangle to be M and the length of a side of the triangle to be b. Express your answer below as pure numbers in units of Mb^2. Place the origin on the midpoint of one side and set the y-axis to be along the symmetry axis.
<h2>SOLVING</h2>
Find the point-slope equation of the line, with the info given
Formula used, 
| result
The equation of the line in this graph is y = 3/2x + 3.
Explanation:
In slope intercept form equations, the initial value is where everything begins. In this equation, that would be at the point (0,3). From there, because it is going up toward the right side, there is a positive slope. The formula for slope is rise over run, so to get our slope, we have to go up 3 units and over 2 units.
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Step-by-step explanation:
