Question

Daniel wanted to know his approximate score on the final exam for his mathematics class. His professor hinted that his score was well above the class average. The professor announced that the mean for the class final exam was 90 with a standard deviation of 7. Given Daniel's z score of 1.67, what is the raw score for Daniel's exam grade?102.45100.00101.6988.17

Answer 1

Answer: 101.69

Step-by-step explanation:

Formula we use to find the z-score :-

$z=\dfrac{x-\mu}{\sigma}$    (1)

Given : $\mu=90$

$\sigma=7$

Daniel's z score : z= 1.67

Let x be the raw score for Daniel's exam grade, then substitute the values of $\mu,\ \sigma\ and \ x$ in (1), we get

$1.67=\dfrac{x-90}{7}\\\\\Rightarrow\ x-90=7\times1.67\\\\\Rightarrow\ x=11.69+90=101.69$

Hence, the raw score for Daniel's exam grade = 101.69