Solve x^2 - 8x = 3 by completing the square. Which is the solution set of the equation?

Mathematics

2 answers:

Alik [6]2 years ago

8 0

Answer:

Step-by-step explanation:

Given

x² - 8x = 3

To complete the square

add (half the coefficient of the x- term)² to both sides

x² + 2(- 4)x + 16 = 3 + 16

(x - 4)² = 19 ( take the square root of both sides )

x - 4 = ± $\sqrt{19}$ ( add 4 to both sides )

x = 4 ± $\sqrt{19}$

Solution set is (4 - $\sqrt{19}$ , 4 + $\sqrt{19}$ )

sp2606 [1]2 years ago

5 0

1st one

Step-by-step explanation:

I have answered ur question

You might be interested in

Please answer I will give BRAINLIEST if i can

N76 [4]

Answer:

Glass A holds the most, It holds more than glass B because of its cone shape.

Step-by-step explanation:

I hope I helped you, now have a good day and good luck!! ;)

7 0

3 years ago

PLS HELP ILL GIVE BRAINLIEST

inysia [295]

<h3>Answer: 14x - 8</h3>

=======================================================

Explanation:

I'll use the quadratic formula to find the roots or x intercepts. This slight detour allows us to factor without having to use guess-and-check methods.

The equation is of the form ax^2+bx+c = 0

a = 12
b = -11
c = -5

This leads to...

$x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(-11)\pm\sqrt{(-11)^2-4(12)(-5)}}{2(12)}\\\\x = \frac{11\pm\sqrt{361}}{24}\\\\x = \frac{11\pm19}{24}\\\\x = \frac{11+19}{24} \ \text{ or } \ x = \frac{11-19}{24}\\\\x = \frac{30}{24} \ \text{ or } \ x = \frac{-8}{24}\\\\x = \frac{5}{4} \ \text{ or } \ x = -\frac{1}{3}$