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vova2212 [387]
3 years ago
7

Complete the equationof the line whose slope is -2 and y-intercept is (0,-8)

Mathematics
1 answer:
zmey [24]3 years ago
5 0

Answer:hope I ain’t latee

Step-by-step explanation:

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What kind of probability is being used when one calculates the probability that a randomly selected adult who works from home an
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What times what equals 64
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3 years ago
Find the midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9)
JulsSmile [24]

The midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9) is \left(\frac{-9}{2}, \frac{-3}{2}\right)

<u>Solution:</u>

Given, two points are (-6, 6) and (-3, -9)

We have to find the midpoint of the segment formed by the given points.

The midpoint of a segment formed by \left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right) is given by:

\text { Mid point } \mathrm{m}=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)

\text { Here in our problem, } x_{1}=-6, y_{1}=6, x_{2}=-3 \text { and } y_{2}=-9

Plugging in the values in formula, we get,

\begin{array}{l}{m=\left(\frac{-6+(-3)}{2}, \frac{6+(-9)}{2}\right)=\left(\frac{-6-3}{2}, \frac{6-9}{2}\right)} \\\\ {=\left(\frac{-9}{2}, \frac{-3}{2}\right)}\end{array}

Hence, the midpoint of the segment is \left(\frac{-9}{2}, \frac{-3}{2}\right)

6 0
3 years ago
write an equation in point-slope form of the line that passes through the point (-2,4) and has a slope of 5
3241004551 [841]

Answer:

y=mx+b     m= slope     b=Y-Intercept

4=5(-2)+b

7 0
3 years ago
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