L=2+W
A=LW
A=(2+W)W
20=2W+W^2
0=W^2+2W-20
use quadratic
fr
aw^2+bw+C=0
w=(-b+/-sqrt(b^2-4ac))/2a
a=1
b=2
c=-20
w=(-2+/-sqrt(2^2-4(1)(-20)))/2(1)
w=(-2+/-sqrt(4+80))/2
w=(-2+/-sqrt(84))/2
w=(-2+/-2sqrt(21))/2
w=1+/-sqrt(21)
aprox
w=-3.58 or 5.58
cannot have negative width
w=5.58
round
w=5.6
sub
l=2+w
l=2+5.6
l=7.6
legnth=7.6m
width=5.6m
Answer:
1890, total cost of lights per week
Step-by-step explanation:
The lights cost 45 dollars per bulb and 6 go out per day, 45×6=270
270 is the cost to replace the bulbs of one day.
270×7=1890. 1890 is the cost for a whole weeks worth of replacing these bulbs.
Answer:
4ft
Step-by-step explanation:
500=pir^2h
r^2=500/(10*pi)
r=3.989ft
35 is the answer35 is the answer35 is the answer
Between -2&-1 is the answer
