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viktelen [127]
3 years ago
15

PLEASE HELP! Record the lengths of the sides of ΔABC and ΔADE.I would appreciate it.

Mathematics
1 answer:
natta225 [31]3 years ago
8 0

AB: 20

BC: 12

AC: 16

AD: 10

DE: 6

AE: 8

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lubasha [3.4K]
Easy first cover kilograms into grams 1kg=1000g. resulting in 10,000g dividing that by the weight of the oranges getting 10,000/200=50 so the answer is 50 oranges. (assuming they all weigh the same)
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3 years ago
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Does anyone know this?
zzz [600]

Answer:

-3

Step-by-step explanation:

Since x=1, we can simplify the equation to 9+7y=-12.

To find the value of 7y, we first have to find what is missing.

-12-9=-21, so 7y has to be equal to -21. -21/7 equals -3, so y=-3.

7 0
3 years ago
Suppose that there are five young women and six young men on an island. Each woman is willing to marry some of the men on the is
pochemuha

Answer:

Based on the current information, the last man remaining unmarried will be a choice between two

Jason marries Anna

Matt marries Elizabeth

Kevin marries Barbara

Larry marries Diane

Carol can marry either Nick or Oscar

Step-by-step explanation:

The basic method to sort which woman will be marrying which man is simple.

We have to extract the choice by comparing choices of each woman side by side and then selecting the least common one and hence sorting one by one.

First, let's name all the women and men

1. Anna

2. Barbara

3. Carol

4. Diane

5. Elizabeth

We will refer to them with the initial letter of their name . A for Anna, B for Barbara, C for Carol, D for Diane, E for Elizabeth.

The men :

1. Jason

2. Larry

3. Matt

4. Kevin

5. Oscar

6. Nick

And they will be referred as J for Jason, L for Larry, M for Matt, K for Kevin, O for Oscar  and N for Nick.

Options for A : J , L ,M

Options for B : K, L

Options for C : J, N , O

Options for D : J, L , N , O

Options for E : J, M

As we can see , no one else wants Kevin other than Barbara so :

Kevin marries Barbara

Moving onwards:

Elizabeth can marry either Jason or Matt,

Meanwhile Anna can marry either Jason , Larry or Matt  

Hence,

Matt marries Eilzabeth

as Anna has two more choices still which are Jason and Larry.

Further, seeing the options for Carol and Diane

Carol can marry either Jason, Nick or Oscar while Diane can marry Larry as well as Jason , Nick and Oscar

We can select Jason as the match for Anna as Larry is also a choice for Diane.

Hence, Jason marries Anna

Now we are left with Larry , Nick and Oscar.

Since Carol can only decide from Nick and Oscar but Diane can decide from Larry, Nick and Oscar. Larry is the ideal option for Diane

so, Larry marries Diane

Now in the end, Carol can either choose between Nick or Oscar.

If she chooses Nick to marry, Oscar is left single

If she chooses Oscar to marry, Nick is left single.

7 0
3 years ago
Jemima was arranging 400 packets of biscuits for a sale. She put 52 packets into a basket and displayed 25% of the remaining pac
stealth61 [152]

Answer:

87% of all the packets of biscuits Jemima displayed on the shelves.

Step-by-step explanation:

400-52=348

so, 348*25%

348*25/100

87

6 0
2 years ago
A stationer pay N18 for a set of pen what must be the selling price if he wants to make a profit of 15%​
Sergio [31]

Answer:

yrbfj kejs l

Step-by-step explanation:

6 0
3 years ago
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