PLEASE HELP! Record the lengths of the sides of ΔABC and ΔADE. I would appreciate it.

6. The mean number of hours of flying time for pilots at Continental Airlines is 37 hours per month (The Wall Street Journal, Fe

SashulF [63]

Answer:

The marginal error is 2.355

Confidence interval is $(34.645,\ 39.355)$

The LB and UB are 34.645 and 39.3555 respectively.

Step-by-step explanation:

Consider the provided information.

n = 49, s = 8.2 c = 95%and $\bar x=37$

Degree of freedom is: n-1 = 49-1 = 48.

$\alpha =\frac{1-c}{2}= \frac{1-0.95}{2}\\\alpha = \frac{0.05}{2}= 0.025$

From the table $t_{\alpha /2}=2.010635$

Marginal error is:

$E=t_{\alpha /2}\times \frac{s}{\sqrt{n}}$

$E=2.0106\times \frac{8.2}{\sqrt{49}}$

$E=2.0106\times \frac{8.2}{7}$

$E=2.0106\times 1.171$

$E=2.355$

Hence, the marginal error is 2.355.

Part (B)

95% confidence interval estimate

$(\bar x-E,\ \bar x+E)$

$(37-2.355,\ 37+2.355)$

$(34.645,\ 39.355)$

Thus, the LB and UB are 34.645 and 39.3555 respectively.

3 0

3 years ago

A student sets up the following equation to convert a measurement. Fill in the missing part of the equation

fomenos

Answer:

We have the equation:

(14 N/mm)*X = Y N/cm

So we want to transform 1/mm to 1/cm.

We know that:

10mm = 1cm

1 = 10mm/1cm (we want to have mm on the numerator, so it cancelates with the mm in the denominator)

then the conversion is from 1/mm to 1/cm is:

X = 10mm/cm

then we have:

(14N/mm)*(10mm/cm) = 140 N/cm

4 0

3 years ago

Y=4x+8 Y=5x+1 I cant figure out this math problem

Crank

If solving for x:
Because both equations are equal to Y, you can set both equations equal to each other:
5x+1=4x+8
Then it's a matter of simplification (subtract the 4x to the left side and subtract the 1 over to the right):
x=7
If solving for Y:
Plug x=7 into either equation and solve:
Y=4(7)+8
Y=36

4 0

3 years ago

a boat on the Potomac River travels the same distance downstream in 2/3 hour as it does going upstream in 1 hour. If the speed o

lord [1]

$\bf \begin{array}{ccccllll}
&distance&rate&time(hrs)\\
&-----&-----&-----\\
upstream&d&r-3&\frac{2}{3}
\\\\
downstream&d&r+3&1
\end{array}\\\\
-----------------------------\\\\
thus\qquad 
\begin{cases}
d=(r-3)\frac{2}{3}
\\\\
d=(r+3)1
\end{cases}\qquad d=d\qquad thus
\\\\\\
(r-3)\cfrac{2}{3}=(r+3)1$

notice, the distance is the same, upstream or downstream, thus is "d" for both

solve for "r"

7 0

3 years ago

2/7(x+4)=−6 solve for x

lara31 [8.8K]

Answer:

x = -25

Step-by-step explanation:

solve for x by simplifying both sides of the equation, then isolating the variable.

4 0

3 years ago

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PLEASE HELP! Record the lengths of the sides of ΔABC and ΔADE.I would appreciate it.