First, let's calculate the horizontal and vertical components of the wind speed (W) and the airplane speed (A), knowing that south is a bearing of 270° and northeast is a bearing of 45°:
Now, let's add the components of the same direction:
To find the resultant bearing (theta), we can use the formula below:
The angle -86° is equivalent to -86 + 360 = 274°.
Therefore the correct option is b.
Answer:
y-intercept = (0,-21)
vertex = (2,-25)
Step-by-step explanation:
Answer:
m∠1=80°
m∠2=112°
m∠3=131°
m∠4=80°
m∠5=37°
Step-by-step explanation:
First you have to find m∠2
To do that find m∠6 (I created this angle shown in pic below)
Find m∠6 by using the sum of all ∠'s in a Δ theorem
m∠6=180°-(63°+49°)
m∠6=68°
Now you can find m∠2 with the supplementary ∠'s theorem
m∠2=180°-68°
m∠2=112°
Then you find m∠5 using the sum of all ∠'s in a Δ theorem
m∠5=180°-(112°+31°)
m∠5=37°
Now you can find m∠1
m∠1=180°-(63°+37°)
m∠1=180°-100°=80°
m∠4 can easily be found too now:
m∠4=180°-(63°+37°)
m∠4=80°
m∠3=180°-49°
m∠3=131°
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☆ Now Let's find value of sin A, cos A and tan A,
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- sin A = Perpendicular/Hypotenus =
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- cos A = Base/Hypotenus =
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- tan A = Perpendicular/Base =
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