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sweet [91]
3 years ago
11

Use the triangle below to find cos V.

Mathematics
1 answer:
Semenov [28]3 years ago
8 0

Answer:

cos\ V = \frac{2\sqrt{29}}{29}

Step-by-step explanation:

Given

The attached triangle

Required

Find cos V

In trigonometry:

cos\theta = \frac{Adjacent}{Hypotenuse}

In this case:

cos V= \frac{TV}{UV}

Where

TV = 6

and

UV^2 = TV^2 + TU^2 -- Pythagoras

UV^2 = 6^2 + 15^2

UV^2 = 261

Take square roots

UV = \sqrt{261

UV = \sqrt{9*29

UV = \sqrt{9} *\sqrt{29

UV = 3\sqrt{29

So:

cos V= \frac{TV}{UV}

cos\ V = \frac{6}{3\sqrt{29}}

cos\ V = \frac{2}{\sqrt{29}}

Rationalize:

cos\ V = \frac{2}{\sqrt{29}}*\frac{\sqrt{29}}{\sqrt{29}}

cos\ V = \frac{2\sqrt{29}}{29}

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