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sweet [91]
2 years ago
11

Use the triangle below to find cos V.

Mathematics
1 answer:
Semenov [28]2 years ago
8 0

Answer:

cos\ V = \frac{2\sqrt{29}}{29}

Step-by-step explanation:

Given

The attached triangle

Required

Find cos V

In trigonometry:

cos\theta = \frac{Adjacent}{Hypotenuse}

In this case:

cos V= \frac{TV}{UV}

Where

TV = 6

and

UV^2 = TV^2 + TU^2 -- Pythagoras

UV^2 = 6^2 + 15^2

UV^2 = 261

Take square roots

UV = \sqrt{261

UV = \sqrt{9*29

UV = \sqrt{9} *\sqrt{29

UV = 3\sqrt{29

So:

cos V= \frac{TV}{UV}

cos\ V = \frac{6}{3\sqrt{29}}

cos\ V = \frac{2}{\sqrt{29}}

Rationalize:

cos\ V = \frac{2}{\sqrt{29}}*\frac{\sqrt{29}}{\sqrt{29}}

cos\ V = \frac{2\sqrt{29}}{29}

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Tyler's mom purchased a savings bond for Tyler. The value of the savings bond increases by 4% each year. One year after it was p
Alla [95]

Answer:

150

Step-by-step explanation:

Since the value of the bond increases by 4% each year and only 1 year passed by then the ROI is not compounded and we only need to find the value before the 4% was implemented. In order to add 4% to a value we would multiply that value by 1.04 which increases that value by 4%. So, to find the value before the interest was added we would need to divide the new value by 1.04 instead.

$156 / 1.04 = $150

Finally, we can see that the value of the bond when Tyler's mom purchased it was 150

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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
Which expression is equivalent to sin^2x-sin x-2/sin x-2
Arturiano [62]
Post the problem from the paper
3 0
3 years ago
Which equations have the same value of x as Three-fifths (30 x minus 15) = 72? Select three options.
DanielleElmas [232]

Answer:

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Step-by-step explanation:

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6 0
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Which ratios are equal to 64 when the scale factor is 8? Select all that apply.
Luden [163]

Answer:

The scaled surface area of a square pyramid to the original surface area.

The scaled area of a triangle to the original area.

Step-by-step explanation:

Suppose that we have a cube with sidelength M.

if we rescale this measure with a scale factor 8, we get 8*M

Now, if previously the area of one side was of order M^2, with the rescaled measure the area will be something like (8*M)^2 = 64*M^2

This means that the ratio of the surfaces/areas will be 64.

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