SOMEONE PLEASE HELP....

Mathematics

1 answer:

Anton [14]3 years ago

6 0

Answer:

Step-by-step explanation:

$(3x+4)(x^2+px+5) \\=3x^3+3px^2+15x+4x^2+4px+20\\=3x^3+(3p+4)x^2+(15+4p)x +20$

since we know that $x^2$ in this expansion is $-23x^{2}$

thus $3p+4=-23\\3p=-27\\p=-9$

Hope that helps!

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